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Varvara68 [4.7K]
3 years ago
6

Drosera magnifica is an organism that was first discovered in 2015.

Physics
1 answer:
mestny [16]3 years ago
3 0

Answer:

The correct answer is - Plantae.

Explanation:

Drosera m<em>agnifica</em> is discovered in 2015 for the first time and the characteristics this organism's cell shows are -

- permanent vacuoles

- surrounded by cellulose layer

Vacuoles are present in both Plantae and Animalia kingdom of the eukaryotic organism but in animal cells, there are small and numerous vacuoles present and they are not permanent whereas in plant cells vacuoles are present permanently.

The cell of an animal cell has no surrounding layer other than cell membrane while in the plant cell there is a supporting and protecting layer of cellulose cell wall present.

On the basis of the given characteristics, it is confirmed that the Drosera magnifica belongs to Plantae kingdom.

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What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 N at an angle of 35° above the
Olegator [25]

The acceleration of the wagon along the ground is 3.6 m/s².

To solve the problem above, we need to use the formula of acceleration as related to force and mass.

Acceleration: This can be defined as the rate of change of velocity.

⇒ Formula:

  • Fcos∅ = ma................. Equation 1

⇒ Where:

  • F = Force
  • ∅ = angle above the horizontal
  • m = mass of the wagon
  • a = acceleration of the wagon

⇒ make a the subject of equation 1

  • a = Fcos∅/m..................... Equation 2

From the question,

⇒ Given:

  • F = 44 N
  • ∅ = 35°
  • m = 10 kg

⇒ Substitute these values into equation 2

  • a = 44(cos35°)/10
  • a = 44(0.8191)/10
  • a = 3.6 m/s²

Hence, The acceleration of the wagon along the ground is 3.6 m/s²

Learn more about acceleration here: brainly.com/question/9408577

3 0
3 years ago
4) You have a 10 ohm resistor connected in series with an ammeter. The voltage applied to the whole circuit is 1.2 volts. At the
GuDViN [60]

Answer:

0.6 Ω

Explanation:

As shown in the diagram below,

Since the resistance and the ammeter are connected in series,

(i) The same amount of current flows through them.

(ii) The sum of their individual individual voltage is equal to the total voltage of the circuit.

Applying ohm's law,

V = IR................ Equation 1

Where V = Voltage across the ammeter, I = current flowing through the ammeter, R = resistance of the ammeter.

make R the subject of the equation

R = V/I............... Equation 2

Given: V = 1.2-0.9 = 0.3 V, I = 0.5 A.

Substitute into equation 2

R = 0.3/0.5

R = 0.6 Ω

3 0
3 years ago
Read 2 more answers
1. While skiing, Sam flies down a hill and hits a jump. He has a mass of 75 kg, and he leaves the jump at 18 m/s. What is his mo
Elenna [48]

1350kgm/s

Explanation:

Given parameters:

Mass of Sam = 75kg

Velocity = 18m/s

Unknown:

Momentum = ?

Solution:

Momentum is the property of a moving body with respect to its mass and velocity.

Objects in motion have momentum. The more the velocity of a body, the more its momentum. Also, the more the mass of an object, the more momentum it possess.

Momentum is a function of the mass and the velocity of a body

   Momentum = mass x velocity

   Momentum = 75 x 18 = 1350kgm/s

learn more:

Conservation of momentum brainly.com/question/2990238

#learnwithBrainly

5 0
4 years ago
Read 2 more answers
A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can
Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

\mu is the coefficient of friction between the tires and the road

m is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

v is the speed of the car

r is the radius of the curve

In this problem,

r = 750 m is the radius

v=85 mph \cdot \frac{1609}{3600}=38.0 m/s is the speed

And solving for \mu, we find the coefficient of friction required to keep the car in circular motion:

\mu = \frac{v^2}{rg}=\frac{38.0^2}{(750)(9.8)}=0.196

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brainly.com/question/2562955  

brainly.com/question/6372960  

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8 0
3 years ago
Describe what happens to the system inside of a refrigerator or freezer in terms of heat transfer, work, and conservation of ene
Over [174]

Answer: A. Work is done on the system and heat is transferred from the system for a net decrease in internal energy.

Explanation:

A refrigerator is a device which dispenses heat from the close system to a warmer area or in the surrounding. By dispensing the heat the internal temperature of the refrigerator drops. The system of refrigerator violates the second law of thermodynamics. As it performs the work to cool the region instead of heating the region. The work is done on the system and the internal energy decreases and the heat energy is liberated to the surrounding area. A refrigerator is an open system.

6 0
3 years ago
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