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Varvara68 [4.7K]
3 years ago
6

Drosera magnifica is an organism that was first discovered in 2015.

Physics
1 answer:
mestny [16]3 years ago
3 0

Answer:

The correct answer is - Plantae.

Explanation:

Drosera m<em>agnifica</em> is discovered in 2015 for the first time and the characteristics this organism's cell shows are -

- permanent vacuoles

- surrounded by cellulose layer

Vacuoles are present in both Plantae and Animalia kingdom of the eukaryotic organism but in animal cells, there are small and numerous vacuoles present and they are not permanent whereas in plant cells vacuoles are present permanently.

The cell of an animal cell has no surrounding layer other than cell membrane while in the plant cell there is a supporting and protecting layer of cellulose cell wall present.

On the basis of the given characteristics, it is confirmed that the Drosera magnifica belongs to Plantae kingdom.

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A 1kg skateboard sits at the top of a ramp 20 fr off the ground . How much potential energy does it have ?
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Answer:

196J

Explanation:

Given parameters:

Mass of skateboard  = 1kg

Height off the ground  = 20m

Unknown:

Potential energy  = ?

Solution:

The potential energy is the energy due to the position of a body above the ground.

It is mathematically expressed as:

      Potential energy  = mass x acceleration due gravity x height

     Potential energy  = 1 x 9.8 x 20  = 196J

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Usually, when the temperture is increased l, what will happen to the ratevof dissolving?
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Which of the following statements are true of solids?
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A 0.50 kg object is at rest. A 2.88 N force to the right acts on the object during a time interval of 1.48 s. a) What is the vel
Murljashka [212]

Answer:

8.5m/s

Explanation:

We are given that

Mass of object=m=0.50 kg

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Force=F=2.88 N

Time=1.48 s

a.We know that

F=ma

Using the formula

2.88=0.50a

a=\frac{2.88}{0.50}=5.76m/s^2

a=\frac{v-u}{t}

Using the formula

5.76=\frac{v-0}{1.48}

v=5.76\times 1.48=8.5m/s

Hence, the velocity of the object at the end of this time interval=8.5m/s

8 0
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A 35.0 g bullet strikes a 50 kg stationary piece of lumber and embeds itself in the wood. The piece of lumber and the bullet fly
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Answer:

12294.31 m/s

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