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3 years ago

Drosera magnifica is an organism that was first discovered in 2015.

Physics

1 answer:

mestny [16]3 years ago

3 0

Answer:

The correct answer is - Plantae.

Explanation:

Drosera magnifica is discovered in 2015 for the first time and the characteristics this organism's cell shows are -

- permanent vacuoles

- surrounded by cellulose layer

Vacuoles are present in both Plantae and Animalia kingdom of the eukaryotic organism but in animal cells, there are small and numerous vacuoles present and they are not permanent whereas in plant cells vacuoles are present permanently.

The cell of an animal cell has no surrounding layer other than cell membrane while in the plant cell there is a supporting and protecting layer of cellulose cell wall present.

On the basis of the given characteristics, it is confirmed that the Drosera magnifica belongs to Plantae kingdom.

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Two cars, one of mass 1400 kg, and the

Vikki [24]

Suppose that, in the x-y plane, the first car is moving to the right so that its velocity is given by the vector

v₁ = (14 m/s) i

and the second car is moving upward so that its velocity vector is

v₂ = (20 m/s) j

Then the total momentum of two cars before their collision is

m₁v₁ + m₂v₂ = (1400 kg) (14 m/s) i + (2300 kg) (20 m/s) j

= (19,600 i + 46,000 j) kg•m/s

Their momentum after the collision is

(1400 kg + 2300 kg) v = (3700 kg) v

where v is the velocity vector of the wreckage.

By conservation of momentum,

(19,600 i + 46,000 j) kg•m/s = (3700 kg) v

Let a and b be the horizontal and vertical components of v, respectively. Then

19,600 kg•m/s = (3700 kg) a ⇒ a ≈ 5.2973 m/s ≈ 5.3 m/s

46,000 kg•m/s = (3700 kg) b ⇒ b ≈ 12.4324 m/s ≈ 12 m/s

so that the final speed of the wreckage is

||v|| = √(a² + b²) ≈ 13.5139 m/s ≈ 14 m/s

3 0

2 years ago

A speeding motorist traveling down a straight highway at 100 km/h passes a parked police car. It takes the police constable 1.0

Lubov Fominskaja [6]

Answer:

t = 7.5 s

Explanation:

The distance traveled by the car at the time of meeting of the two cars must be the same. First, we calculate the distance traveled by the police car. For that we use 2nd equation of motion. Here, we take the time when police car starts to be reference. So,

s₁ = Vi t + (0.5)gt²

where,

s₁ = distance traveled by police car

Vi = Initial Velocity = 0 m/s

t = time taken

Therefore,

s₁ = (0 m/s)(t) + (0.5)(9.8 m/s²)t²

s₁ = 4.9 t²

Now, we calculate the distance traveled by the car. For constant speed and time to be 1 second more than the police car time, due to car starting time, we get:

s₂ = Vt = V(t + 1)

where,

s₂ = distance traveled by car

V = Velocity of car = (100 km/h)(1000 m/1 km)(1 h/ 3600 s) = 27.78 m/s

Therefore,

s₂ = 27.78 t + 27.78

Now, we know that at the time of meeting:

s₁ = s₂

4.9 t² = 27.78 t + 27.78

4.9 t² - 270.78 t - 27.78 = 0

solving the equation and choosing the positive root:

t = 6.5 s

since, we want to know the time from the moment car crossed police car. Therefore, we add 1 second of starting time in this.

t = 6.5 s + 1 s

t = 7.5 s

6 0

3 years ago

Why can water dissolve some ionic compounds, like NH4Cl, as well as some nonionic compounds, like methanol?

nirvana33 [79]

I think that’s the answer u r looking for

4 0

3 years ago

Read 2 more answers

A compressed spring is compressed between a 5kg and 3 kg cart, respectively. When the spring is released, what will be the same

stira [4]

The momentum of the two carts will be the same

Explanation:

First of all, we notice that the system consisting of the two carts + the spring is an isolated system: this means that there are no external forces acting on it.

As a result, the total momentum of the system must be conserved.

Since the spring is at rest, the total momentum of the system after the two carts are released is:

$p_f = p_1 + p_2$

where

$p_1$ is the momentum of the 1st cart

$p_2$ is the momentum of the 2nd cart

The total momentum of the system at the beginning, when the spring is compressed, is zero:

$p_i=0$

Since the total momentum must be conserved, we have:

$p_i = p_f\\0 = p_1 + p_2\\\rightarrow p_2 = -p_1$

Which means that the two carts will have equal and opposite momenta.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

4 0

3 years ago

The instant before a batter hits a 0.14-kilogram baseball, the velocity of the ball is 45 meters per second west. The instant af

NemiM [27]

(1) The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is 8,000 m/s² east.

(2) The magnitude of the average force the Bat exerts on the ball while they are in contact is 1,120 N.

The given parameters:

Mass of the baseball, m = 0.14 kg
Initial velocity of the baseball, u = 45 m/s west (negative direction)
Final velocity of the baseball, v = 35 m/s east (positive direction)
Time of contact, t = 0.01 s

The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is calculated as follows:

$a = \frac{v- u}{t} \\\\a = \frac{35 - (-45)}{0.01} \\\\a = \frac{80}{0.01} \\\\a = 8,000 \ m/s^2$

The magnitude of the average force the Bat exerts on the ball while they are in contact is calculated as follows;

$F = ma\\\\F = 0.14 \times 8,000\\\\F = 1,120 \ N$

Learn more about average force here: brainly.com/question/16200276

4 0

2 years ago