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NNADVOKAT [17]
2 years ago
9

Gerard is measuring the speed of a remote-controlled airplane. He measures that the airplane travels 110 m in 5.4 seconds, givin

g a speed of 20 m/s. What will Gerard need to change, if he wants to get a more precise value for speed
Physics
1 answer:
netineya [11]2 years ago
3 0

Gerard need to change the Acceleration.

<h3>What is speed?</h3>

Speed is defined as the distance travelled by an object in  a unit time.

Mathematically ,

Speed =\frac{Distance}{Time}

Here the given values are:

Distance = 110m and  time = 5.4 s

Speed = \frac{110}{5.4} = 20 m/s

For increasing the speed he need to change the acceleration.

Which is define as the  rate at which velocity changes with time, in terms of both speed and direction.

Any change in the velocity of an object results in an acceleration , increasing speed (what people usually mean when they say acceleration).

learn more about speed: brainly.com/question/7359669

#SPJ1

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Substances can undergo physical changes or chemical changes. what is the difference between these two kinds of changes
soldi70 [24.7K]
Physical changes are those change which just externally or physically change the state of the object . for example : water boils and evaporates... here the state is just changing from liquid to vapour while the composition is the same.

chemical changes are those which bring about a change in the composition of a substance. for example: burning of paper changes into ash .
8 0
3 years ago
Read 2 more answers
Work &amp; Power Problems
Artyom0805 [142]

Answer:

1. Unit for work is measured in Joules.

Formula for work is power * time taken

2 The unit for force is Newton

A work done in lifting a jar of water

3. The unit for measuring power is Joules.

The formula for measuring power is work done/time taken

6 0
4 years ago
An object weighs 10N on earth .what is the objects weight on a planet one tenth the earths mass and one half its radius?
earnstyle [38]
We know, weight = mass * gravity 
10 = m * 9.8
m = 10/9.8 = 1.02 Kg

Now, Let, the gravity of that planet = g'
g' = m/r²   [m,r = mass & radius of that planet ]
g' = M/10 / (1/2R)²   [M, R = mass & radius of Earth ]
g' = 4M / 10R²
g' = 2/5 * M/R²
g' = 2/5 * g   
g' = 2/5 * 9.8
g' = 3.92

Weight on that planet = planet's gravity * mass
W' = 3.92 * 1.02
W' = 4 N

In short, Your Answer would be 4 Newtons

Hope this helps!
3 0
3 years ago
Sound exits a diffraction horn loudspeaker through a rectangular opening like a small doorway. Such a loudspeaker is mounted out
blondinia [14]

Answer:

\theta = 20.98 degree

Explanation:

As we know that the speed of the sound is given as

v = 332 + 0.6 t

now at t = 273 k = 0 degree

v = 332 m/s

so we have

a sin\theta = N\lambda

a sin\theta = N(\frac{v_1}{f})

now when temperature is changed to 313 K we have

t = 313 - 273 = 40 degree

now we have

v = 332 + (0.6)(40)

v_2 = 356 m/s

a sin\theta' = N(\frac{v_2}{f})

now from two equations we have

\frac{sin19.5}{sin\theta} = \frac{332}{356}

so we have

sin\theta = 0.358

\theta = 20.98 degree

7 0
3 years ago
An open pipe of length 0.39 m vibrates in the third harmonic with a frequency of 1400 Hz what is the distance from the center of
Svetach [21]

Length of the pipe = 0.39 m

Number of harmonics = 3

Now there are 3 loops so here we can say

3\times \frac{\lambda}{2} = 0.39

\lambda = 0.26 m

now here at the center of the pipe it will form Node

we need to find the distance of nearest antinode

So distance between node and its nearest antinode will be

d = \frac{\lambda}{4}

d = \frac{0.26}{4} = 0.065 m = 6.5 cm

So the distance will be 6.5 cm

3 0
3 years ago
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