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3 years ago

PLEASE HELP!!!! HURY

Chemistry

1 answer:

tester [92]3 years ago

3 0

Answer: UwU

Explanation:

i dont really have an answer to that question however i want to remind you that your are an amazing person and that you will ahchieve all your goals god bless you :)

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The atomic number of an element that has 9 protons 9 electrons and 10 neutrons is?

natali 33 [55]

Answer:

nor its just

Explanation:

9 i need answer to be longer so im typing this out

7 0

3 years ago

For the reaction 2NH3(g)↽−−⇀3H2(g)+N2(g) 2 NH 3 ( g ) ↽ − − ⇀ 3 H 2 ( g ) + N 2 ( g ) the equilibrium concentrations were found

forsale [732]

Answer:

0.324

Explanation:

The following data were obtained from the question:

Concentration of NH3, [NH3] = 0.25 M

Concentration of H2, [H2] = 0.3 M

Concentration of N2, [N2] = 0.75 M

Equilibrium constant (Kc) =.?

The balanced equation for the reaction is given below:

2NH3 <==> 3H2 + N2

The equilibrium constant, Kc for a given reaction is the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient. Thus, the equilibrium constant for the above reaction can be obtained as illustrated below:

Kc = [H2]³ [N2] / [NH3]²

Concentration of NH3, [NH3] = 0.25 M

Concentration of H2, [H2] = 0.3 M

Concentration of N2, [N2] = 0.75 M

Equilibrium constant (Kc) =.?

Kc = [H2]³ [N2] / [NH3]²

Kc = [0.3]³ × [0.75] / [0.25]²

Kc = (0.027 × 0.75) / 0.0625

Kc = 0.02025 / 0.0625

Kc = 0.324

Therefore, the equilibrium constant for the reaction is 0.324

4 0

3 years ago

Can someone help please?

attashe74 [19]

<h3>Take the weighted average of the individual isotopes.</h3><h3 /><h3>Explanation:</h3><h3>63</h3><h3>C</h3><h3>u</h3><h3> has </h3><h3>69.2</h3><h3>%</h3><h3> abundance.</h3><h3 /><h3>65</h3><h3>C</h3><h3>u</h3><h3> has </h3><h3>30.8</h3><h3>%</h3><h3> abundance.</h3><h3 /><h3>So, the weighted average is </h3><h3>62.93</h3><h3>×</h3><h3>69.2</h3><h3>%</h3><h3> </h3><h3>+</h3><h3> </h3><h3>64.93</h3><h3>×</h3><h3>30.8</h3><h3>%</h3><h3> </h3><h3>=</h3><h3> </h3><h3>63.55</h3><h3> </h3><h3>amu</h3><h3> .</h3><h3 /><h3>If we look at the Periodic Table, copper metal (a mixture of isotopes but </h3><h3>63</h3><h3>C</h3><h3>u</h3><h3> and </h3><h3>65</h3><h3>C</h3><h3>u</h3><h3> predominate) has an approximate atomic mass of </h3><h3>63.55</h3><h3> </h3><h3>g</h3><h3>⋅</h3><h3>m</h3><h3>o</h3><h3>l</h3><h3>−</h3><h3>1</h3><h3> , so we know we are right.</h3>

4 0

3 years ago

Read 2 more answers

Give the following for SO2 and BrF5:

frosja888 [35]

Answer:

The given molecules are SO2 and BrF5.

Explanation:

Consider the molecule SO2:

The central atom is S.

The number of domains on S in this molecule is three.

Domain geometry is trigonal planar.