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Ilia_Sergeevich [38]
3 years ago
10

Egal loggers got away with 4 acres of trees at a reserve in central Mexico. That number represents a 97 percent decline from two

years prior. How many acres of trees did the illegal loggers get away with two years prior? Round the answer to the nearest acre.
Mathematics
1 answer:
geniusboy [140]3 years ago
6 0

Answer: with 133.33 acres of trees

Step-by-step explanation:

4 acres of trees, is a 97% decrease of the previous amount.

This means that if the previous amount was X, then 4 acres is 3% (or 0.03 in decimal form) of X, or:

4 acres = 0.03*X

Now we can solve this for X as:

X = 4acres/0.03 = 133.33 acres

The illegal loggers got away with 133.33 acres of trees

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Find P(x > 120) provided that it is known that
tresset_1 [31]

The probability when x is greater than 120 is 0.0367. Then the correct option is D.

<h3>What is a normal distribution?</h3>

The Gaussian Distribution is another name for it. The most significant continuous probability distribution is this one. Because the curve resembles a bell, it is also known as a bell curve.

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

The mean is 95 and the standard deviation is 14. Then the probability when x > 120 will be

The z-score will be

z = (120 - 95)/ 14

z = 1.7857

Then the probability will be

P(x > 120) = P(z > 1.7857)

P(x > 120) = 1 - P(x<120)

P(x > 120) = 1 - 0.96293

P(x > 120) = 0.0367

More about the normal distribution link is given below.

brainly.com/question/12421652

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3 0
2 years ago
Ms. Pendleton’s bedroom is a shape of a rectangle. The width of the room is 16 feet and length is four more feet than the width.
QveST [7]

Answer:

The answer to your question is Perimeter = 64 ft

Step-by-step explanation:

Data

width = 16 ft

length = width + 4 ft

Perimeter = ?

Process

1.- Calculate the length

Length = 14 + 4 = 18 ft

2.- Look for the formula of the perimeter

Perimeter = 2(length) + 2(width)

3.- Substitution

Perimeter = 2(18) + 2(14)

4.- Simplification

Perimeter = 36 + 28

5.- Result

Perimeter = 64 ft

6 0
3 years ago
What is the point slope equation of the line that passes through (9,-1) and has a slope of 5
Natalka [10]

Answer:

y=5x+46

Step-by-step explanation:

apply point

-1=5(9)+n

-1=45+n

n=-46

y=5x+46

7 0
2 years ago
Read 2 more answers
Dinesh has 28 points in a trivia game. He answers a question correctly and earns 35 points. Then, he answers a multipart questio
ioda

Answer:

The answer for the problem would be -12

Step-by-step explanation:

(28+35) = 63

63-75= -12

6 0
3 years ago
Hello people ~
Luden [163]

Cone details:

  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (\sqrt{20h - h^2})^2  \  ( h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20h - h^2)  (h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20 - h) (h) ( h)

\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

<u>apply chain rule</u>

\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

\Longrightarrow \sf 40h-3h^2=0

\Longrightarrow \sf h(40-3h)=0

\Longrightarrow \sf h=0, \ 40-3h=0

\Longrightarrow \sf  h=0,\:h=\dfrac{40}{3}<u />

<u>maximum volume:</u>                <u>when h = 40/3</u>

\sf \Longrightarrow max=  \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )

\sf \Longrightarrow maximum= 1241.123 \ cm^3

<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

6 0
2 years ago
Read 2 more answers
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