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Pavlova-9 [17]
3 years ago
10

A fossilized leaf contains 24% of its normal amount of carbon 14. how old is the fossil (to the nearest year)? use 5600 years as

the half-life of carbon 14.
Chemistry
1 answer:
sergij07 [2.7K]3 years ago
7 0
The Half life is the time taken for a radioisotope or a radioactive substance to decay by half its original amount. The half life of carbon 14 is 5600 years. 
Original mass is 100%
Remaining amount is 24% 
Therefore; 0.24 = 1 × (1/2)^n
                     n = log 0.24/log 0.5
                        = 2.06
therefore, the age of the fossil is 5600×2.06
 = 11529.8 
 ≈ 11529 years

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lbvjy [14]

Answer:

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5. It uses the process of fission.

6. Fission involves the splitting of radioactive elements into smaller particles/compounds while Fusion involves combining of two or more atomic nuclei to form one or more different atomic nuclei and subatomic particles.

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6 0
3 years ago
At 338 mm hg and 72 c a sample of carbon monoxide gas occupies a volune of 0.225 L the gas transferred to a 1.50 L flask and the
Elis [28]

Answer:

P₂  = 0.09 atm

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 0.225 L

Initial pressure = 338 mmHg (338/760 =0.445 atm)

Initial temperature = 72 °C (72 +273 = 345 K)

Final temperature = -15°C (-15+273 = 258 K)

Final volume = 1.50 L

Final pressure = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

P₂ = P₁V₁ T₂/ T₁ V₂ 

P₂ = 0.445 atm × 0.225 L × 258 K / 345 K × 1.50 L

P₂  =  25.83 atm .L.  K  / 293 K . L

P₂  = 0.09 atm

7 0
3 years ago
The carbon dioxide gas that was generated during this reaction was collected at 295K and 125 kPa. If 43.2 L of carbon dioxidegas
Vladimir [108]

Answer:

The balanced equation for this reaction is C2H2 + 502 + 4H2O + 3C02. What volume of carbon dioxide is produced when 2.8 L of oxygen are consumed? 25Explanation:

8 0
2 years ago
Calculate the electrical energy per gram of anode material for the following reaction at 298 K:
solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, <em>n</em>, equals 0.144 moles for each gram of the anode.

Let w_\text{max} represents the electrical energy produced.

w_\text{max} = n \cdot F \cdot E_\text{cell}, where

  • <em>n</em> is the <em>number of moles</em> electrons transferred,
  • <em>F</em> is the Faraday's constant,
  • <em>E</em>_\text{cell} is the cell potential,

<em>n </em>= 0.144 mol, as shown above, and

<em>F </em>= 96.486 kJ / (\text{V} \cdot \text{mol} \; \text{e}^{-}).

Therefore,

w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}.

3 0
3 years ago
2 HCl + Na2SO4 &gt; 2 NaCl + H2SO4
Cerrena [4.2K]

Answer:

15

Explanation:

8 0
2 years ago
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