3 years ago

Find the annual percentage rate of change for the population of Oregon. In 2000, there were 4.8

Mathematics

1 answer:

MrRa [10]3 years ago

5 0

Answer:

The annual percentage rate of change for the population of Oregon is of 8.125%.

Step-by-step explanation:

Total percentage change:

Change multiplied by 100 and divided by the initial value.

Change: 8.7 - 4.8 = 3.9 million

Initial value: 4.8

Percentage change: 3.9*100/4.8 = 81.25%

Annual percentage rate of change

81.25% during 10 years(from 2000 to 2010).

So, per year

81.25%/10 = 8.125%

The annual percentage rate of change for the population of Oregon is of 8.125%.

You might be interested in

Factor n(2n+3)+4(2n-3)

zavuch27 [327]

The answer would be 2n^2+3n+ 8n-1

3 0

2 years ago

A car salesman sold three hybrid cars last week. The cars come in red, white, and black. A sale is listed as RWB if a red car wa

marysya [2.9K]

Answer:

black car

Step-by-step explanation:

cbuerif3qopvb vr3yiqtolfhbu;p

6 0

3 years ago

#1: 36 in.=__________ft?

KatRina [158]

1. 3 foot
2. 4 yard
3. 1 yard
4. 4 foot
5. 6 foot
6. 108 inch
7. 7.5 foot
8. 66 inch
9. 216 inch
10. 36 foot
11. 3.75 foot
12. 30 yard

3 0

3 years ago

Use the cosine ratio or the inverse cosine to solve for x. Round your answer to the nearest tenth.

maria [59]

Answer:

x ≈ 12.6 m

Step-by-step explanation:

By using cosine ratio in the given right triangle RTS,

cos(S)° = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

cos(33)° = $\frac{\text{ST}}{\text{SR}}$

cos(33)° = $\frac{x}{15}$

x = 15.cos(33)°

x = 12.58

x ≈ 12.6 m

Therefore, measure of side ST = 12.6 m is the answer.

7 0

3 years ago

PLEASE HELP! I need help on this

Alja [10]

99+2x=180
x=40.5
99>
40.5

6 0

3 years ago