3 years ago

Please any one can help solving this question

Physics

1 answer:

klasskru [66]3 years ago

4 0

Which part are you stuck on? Or is it all of these questions?

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To solve this problem we will apply the concepts related to the change in length in proportion to the area and volume. We will define the states of the lengths in their final and initial state and later with the given relationship, we will extrapolate these measures to the area and volume

The initial measures,

$\text{Initial Length} = L$

$\text{Initial surface Area} = 6L^2$ (Surface of a Cube)

$\text{Initial Volume} = L^3$

The final measures

$\text{Final Length} = L_f$

$\text{Final surface area} = 6L_f^2$

$\text{Final Volume} = L_f^3$

Given,

$\frac{(SA)_f}{(SA)_i} = 2$

Now applying the same relation we have that

$(\frac{L_f}{L_i})^2 = 2$

$\frac{L_f}{L_i} = \sqrt{2}$

The relation with volume would be

$\frac{(Volume)_f}{(Volume)_i} = (\frac{L_f}{L_i})^3$

$\frac{(Volume)_f}{(Volume)_i} = (\sqrt{2})^3$

$\frac{(Volume)_f}{(Volume)_i} = (2\sqrt{2})$

$\frac{(Volume)_f}{(Volume)_i} = 2.83$

Volume of the cube change by a factor of 2.83

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