1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serga [27]
3 years ago
13

What would this be?

Physics
1 answer:
soldi70 [24.7K]3 years ago
7 0
The first one is the last answer and the seconds one is the second answer
You might be interested in
Each of the following figures shows Earth with a different axis tilt. (Assume that Earth's rotation period is unchanged.) Each a
mart [117]

Answer:

 0º - 23.5º - 45º - 90º

Explanation:

The inclination angle of the Earth's axis with respect to its orbit around the Sun, determines that the duration enters the day and the night is different.

If it is not inclined (angle 0º) the two and niches have the same hardness

If the angle were very high (about 90º) the night would be very long, about half of the orbit period about six months.

Based on this presentation we can answer the question

The Sumo exposition from highest to lowest is

    0º - 23.5º - 45º - 90º

3 0
3 years ago
Write a question you would like to see on a quiz to calculate NET FORCE.
Pie

Answer:

How do you find the net force?

Explanation:

i think this is want you asked for?

5 0
3 years ago
Define energy and provide examples of potential and kinetic energy
In-s [12.5K]

Energy is the capacity for doing work..

Kinetic energy - Moving car

Potential energy - flowing water up the hill

6 0
3 years ago
How much heat energy is required to raise the temperature of 20 kilograms of water from 0°c to 35°c?
saveliy_v [14]
Energy required = Specific Heat × mass × change in temp. 
<span>Specific Heat (Cp) water = 4.186kJ/kgC </span>
<span>Mass = 20kg </span>
<span>Change in temperature = 35C - 0C = 35C </span>

<span>Q = 4.186kJ/kgC × 20kg × 35C = 293.02kJ     hope this helps! (:</span>
6 0
3 years ago
Read 2 more answers
A small rocket with mass 20.0 kg is moving in free fall toward the earth. Air resistance can be neglected. When the rocket is 80
Mekhanik [1.2K]

Answer:

= 308.5 N

Explanation:

acceleration  of rocket for safe landing

v_{y} ^{2} = v_{0} ^{2} +2ay

a = \frac{v_{y}^{2} - v_{0}^{2}  }{2y}

v_{0} = initial velocity

v_{y} =final Velocity

m = mass of rocket

\frac{0^{2} - 30^{2}  }{2\times80}

-5.625 m/s^{2}

Upward force

F - mg = ma

F = ma+ mg

F = m(a+g)

m= mass

a = 5.625 m/s^{2}

g = 9.8m/s^{2}

= 20(5.625 m/s^{2}+ 9.8m/s^{2})

= 308.5 N

7 0
3 years ago
Other questions:
  • #1: What did Robert Millikan's oil drop experiment prove?
    5·1 answer
  • A ball is thrown forward at 5 m/s how would the path of the ball differ on earth than on the moon
    7·2 answers
  • Why do cities located in the west have different climates and temperatures in the east cities?
    7·1 answer
  • Jessie just started a new training program at work that grants the trainees much more control over their training. Since Jessie
    5·1 answer
  • Generally, what will happen to most liquids if the temperature is increased?
    7·2 answers
  • In what scenario will an athletes wrist be under tension
    15·1 answer
  • Stored energy in an object due to its position is
    7·2 answers
  • What is a frequency of a ships whistle if the velocity of sound is 340 meters/ second and the wave length is 1.70?
    5·1 answer
  • Anyone who wants to shw booooobs than u can see my body/cqg-fhfh-ptx​
    7·1 answer
  • A student's calculation for the work done on an object is shown.
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!