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2 years ago

In a surface wave (such as a water wave), particles __________.

Physics

2 answers:

soldi70 [24.7K]2 years ago

8 0

Answer

In a surface wave (such as a water wave), particles <u>like water molecule undergoes circular motion.</u>

Explanation:

surface waves are the waves which does not possess transverse or longitudinal nature. In surface waves (water waves) all the particles of the bulk medium(water) does not moves in perpendicular direction or in parallel direction with respect to energy transport direction. In surface wave only surface particles moves in circular motion.

For example when we through a stone in water that time only surface particles moves in circular direction and it creates ripples.

weqwewe [10]2 years ago

7 0

Particles similar to a water wave will travel away from the source. On the Earth's surface this would be shown as an aftershock. On the surface of water, the waves would travel in ripples.

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rodikova [14]

Answer:

152,155 J

Explanation:

115,333 + 36,822 = 152,155J

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2 years ago

A family has a furnace that uses natural gas to heat their home. They are moving to an area that offers the option of using ener

Murrr4er [49]

The disadvantage will the family most likely face by making this switch is that solar power has a less reliable production of heat.Option A is correct.

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Hence option A is correct,

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1 year ago

g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart

weeeeeb [17]

Complete Question

A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.

Answer:

The value $v_2 = 4 \sqrt{10} \ m/s$

Explanation:

From the question we are told that

The charge on the first sphere is $q_1 = 2\mu C = 2*10^{-6} \ C$

The charge on the second sphere is $q_2 = 8 \mu C = 8*10^{-6} \ C$

The mass of the second charge is $m = 1.50 \ g = 1.50 *10^{-3} \ kg$

The distance apart is $d = 0.4 \ m$

The speed of the second sphere is $v_1 = 20 \ ms^{-1}$

Generally the total energy possessed by when $q_2$ and $q_1$ are separated by $0.8 \ m$ is mathematically represented

$Q = KE + U$

Here KE is the kinetic energy which is mathematically represented as

$KE = \frac{1 }{2} m (v_1)^2$

substituting value

$KE = \frac{1 }{2} * ( 1.50 *10^{-3}) (20 )^2$

$KE = 0.3 \ J$

And U is the potential energy which is mathematically represented as

$U = \frac{k * q_1 * q_2 }{d }$

substituting values

$U = \frac{9*10^9 * 2*10^{-6} * 8*10^{-6} }{0.8 }$

$U = 0.18 \ J$

$Q = 0.3 + 0.18$

$Q = 0.48 \ J$

Generally the total energy possessed by when $q_2$ and $q_1$ are separated by $0.4 \ m$ is mathematically represented

$Q_f = KE_f + U_f$

Here $KE_f$ is the kinetic energy which is mathematically represented as

$KE_f = \frac{1 }{2} m (v_2^2$

substituting value

$KE_f = \frac{1 }{2} * ( 1.50 *10^{-3}) (v_2 )^2$

$KE_f = 7.50 *10^{ -4} (v_2 )^2$

And $U_f$ is the potential energy which is mathematically represented as

$U_f = \frac{k * q_1 * q_2 }{d }$

substituting values

$U_f = \frac{9*10^9 * 2*10^{-6} * 8*10^{-6} }{0.4 }$

$U_f = 0.36 \ J$

From the law of energy conservation

$Q = Q_f$

$0.48 = 0.36 +(7.50 *10^{-4} v_2^2)$

$v_2 = 4 \sqrt{10} \ m/s$

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2 years ago

A building is being knocked down with a wrecking ball, which is a big metal sphere that swings on a 12-m-long cable. You are (un

leva [86]

Because you know that gravity is in m/s^2 so, period will be measured in seconds. You know the cable is 12m long and gravity is 9.81 solve for T (period) 2π12sqrt(9.81)=6.94922

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3 years ago

Read 2 more answers

The y-component of the force F which a person exerts on the handle of the box wrench is known to be 86 lb. Determine the x-compo

emmainna [20.7K]

Answer:

x-component of force is 38.18 lb where as magnitude of Force is 93.16

Explanation:

Fy of the force F exerted on the handle of the box wrench = 86 lb

Considering the triangle in Fig 1

magnitude of perpendicular = P = 12

magnitude of base = B = 5