The most i can help with is Saliva glands or salivary glands
Answer:
Explanation:
Given ,
dv / dt = k ( 160 - v )
dv / ( 160 - v ) = kdt
ln ( 160 - v ) = kt + c , where c is a constant
when t = 0 , v = 0
Putting the values , we have
c = ln 160
ln ( 160 - v ) = kt + ln 160
ln ( 160 - v / 160 ) = kt
(160 - v ) / 160 = 
1 - v / 160 = 
v / 160 = 1 - 
v = 160 ( 1 -
)
differentiating ,
dv / dt = - 160k 
acceleration a = - 160k 
given when t = 0 , a = 280
280 = - 160 k
k = - 175
a = - 160 x - 175 
a = 28000 
when a = 128 t = ?
128 = 28000 
= .00457
Answer:
a) T ’= 0.999 s
, b) t = 3596.4 s
Explanation:
The angular velocity of a simple pendulum is
w = √g / L
The angular velocity, frequency and period are related
w = 2π f = 2π / T
2π / T = √ g / L
T = 2π √ L / g
L = T² g / 4π²
L = 1² 9.8 / 4π²
L = 0.248 m
To know the effect of the temperature change let's use the thermal expansion ratios
ΔL = α L ΔT
ΔL = 24 10⁻⁶ 0.248 (-4 - 20)
ΔL = 142.8 10⁻⁶ m
Lf - L = -142. 8 10⁻⁶
Lf = 142.8 10⁻⁶ + 0.248
Lf = 0.2479 m
Let's calculate new period
T ’= 2π √ L / g
T ’= 2π √ (0.2479 / 9.8)
T ’= 0.999 s
We can see that the value of the period is reduced so that the clock is delayed
b) change of time in 1 hour
When the clock is at 20 ° C in one hour it performs 3600 oscillations, for the new period the time of this number of oscillations is
t = 3600 0.999
t = 3596.4 s
Therefore the clock is delayed almost 4 s
Answer:
Pheasants and partridge are common and their viable population in the reserve permits controlled hunting. Endangered animals in the reserve include Musk deer, Wolf, Red panda, Cheer pheasant and Danphe. The hunting license is issued by the Department of National Parks and Wildlife Conservation.
HOPE THIS HELPS, HAVE A GREAT DAY!!
Explanation: