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dlinn [17]
2 years ago
9

100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POI

NTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS

Chemistry
2 answers:
Luba_88 [7]2 years ago
6 0

Answer:

Explanation:

#2 is answered so here is for #3:

Knowns: 100mL of solution; concentration of 0.7M

Unknown: number of moles

Equation: number of moles = volume * concentration

Plug and Chug: number of moles = 100/1000 * 0.7 = 0.07 mole

Final Answer: 0.07mole

pantera1 [17]2 years ago
5 0

Answer:

2.2 moles

Explanation:

n = CV

n = 0.4×5.50

n=2.2 moles

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What amount of SeC16 is needed to produce 4.45 mol of chlorine gas in the
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Answer:

1.48 moles of SeCl6 are needed

Explanation:

Based on the reaction:

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<em>1 mole of SeCl6 reacts producing 3 moles of Cl2.</em>

To solve this question we need to use the conversion factor:

1mol SeCl6 = 3mol Cl2

As we want to produce 4.45 moles of Cl2, we need:

4.45 mol Cl2 * (1mol SeCl6 / 3mol Cl2) =

<h3>1.48 moles of SeCl6 are needed</h3>
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URGENT!! Chemistry gurus-- I summon thee!
Elina [12.6K]

1. Molarity : 0.25 M

2. mol CH₄ = 7.4 moles

mol O₂ = 14.8 moles

<h3>Further explanation</h3>

1.

Given

83.2 g CuCl2 in 2.5 liters of water

Required

the molarity

Solution

Molarity : mol solute per liter of solution(not per liter of solvent)

  • mol solute

mol solute = mol CuCl₂

mol CuCl₂ = mass : MW CuCl₂

mol CuCl₂ = 83.2 : 134.45

mol CuCl₂ = 0.619

  • Molarity

Molarity(M) = mol : V

Assume density CuCl₂ = 3.39 g/cm³

volume CuCl₂ = 8.32 g : 3.39 g/cm³ = 2.45 cm³=2.45 x 10⁻³ L

With this small volume value of CuCl₂, the volume of the solute is sometimes neglected in calculating molarity

volume of solution = 2.5 L + 2.45 x 10⁻³ L = 2.50245 L

Molarity(M) = mol : V

M = 0.619 : 2.50245 L = 0.247≈0.25

2.

Given

Reaction

The correct balanced reaction:

CH4 + 2O2 → CO2 + 2H2O

7.4 moles CO2

Required

moles of methane (CH4) and oxygen gas (O2)

Solution

From the equation, mol ratio of CO₂ : CH₄ : O₂ = 1 : 1 : 2

mol CH₄ = mol CO₂ = 7.4 moles

mol O₂ = 2 x mol CO₂ = 2 x 7.4 moles = 14.8 moles

3 0
3 years ago
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