100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POI
NTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS
2 answers:
You might be interested in
Answer:- B. 4.65 g.
Solution:- The given balanced equation is:
It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.
Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.
Molar mass of = 2(107.87)+32.06 = 247.8 g per mol
The dimensional set up for the complete problem is:
=
So, the correct choice is B. 4.65 g.
Answer:
A) Alkili Metal
B) Basic Metal
C) Transition Metal
D) Semimetal
E) Alkiline Earth
F) Actinide
G) Nonmetal
H) Noble Gas
I) Transitional Metal
Hope This Helps
