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dlinn [17]
1 year ago
9

100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POI

NTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS

Chemistry
2 answers:
Luba_88 [7]1 year ago
6 0

Answer:

Explanation:

#2 is answered so here is for #3:

Knowns: 100mL of solution; concentration of 0.7M

Unknown: number of moles

Equation: number of moles = volume * concentration

Plug and Chug: number of moles = 100/1000 * 0.7 = 0.07 mole

Final Answer: 0.07mole

pantera1 [17]1 year ago
5 0

Answer:

2.2 moles

Explanation:

n = CV

n = 0.4×5.50

n=2.2 moles

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An average human being has about 5.0 L of blood in his or her body. If an average person were to eat 37.7 g of sugar (sucrose, ,
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Answer: 0.0220275 M

Explanation:

So, we are given the following data or parameters which are going to help in solving this particular Question/problem.

=> Averagely, we have the volume = 5.0 L of blood in human body .

=> Mass of sugar eaten = 37.7 g of sugar (sucrose, 342.30 g/mol).

Therefore, the molarity of the blood sugar change can be calculated as below:

The molarity of the blood sugar change = (1/ volume) × mass/molar mass.

Thus, the molarity of the blood sugar change = (1/5) × 37.7/342.30 = 0.0220275 M.

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How many carbon atoms are there in .500 mol of CO2?
AURORKA [14]

Answer: There are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

Explanation:

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Here we have explain that the maximum possible electrons present in nitrogen valence shell is 8 whereas in phosphorous 12 valence electrons are present.

Although both nitrogen (N) and phosphorous (P) belongs to the same series there are several properties which are different between both the element. The number of electrons present in nitrogen is seven which are present in the -s and -p orbitals. The electronic configuration of nitrogen is 1s²2s²2p³. In which the outermost electrons are the valence electrons i.e. 5 valence electrons are present. The maximum orbitals are possible under the principal quantum number 2 are -s and -p orbitals. Now the maximum capacity of the p orbital to contain 6 electrons, as it is half filled in nitrogen another 3 electrons can be incorporated. Thus the maximum number of electrons can be present in nitrogen is 10 among which 8 is the valence electrons.

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