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3 years ago

If a 0.7 M solution of Ca(OH)2 dissociates completely in water, what is the final [OH-]?

Chemistry

1 answer:

IceJOKER [234]3 years ago

3 0

Answer:

1.40 M [OH⁻]

Explanation:

This compound dissociates into 3 ions, but since we are asked about [OH⁻], it's only 2. Therefore, multiply the molarity of the solution by the number of ions that [OH⁻] dissociates into:

2 × 0.70 M = 1.40 M

Hope this helps! Sorry that you got a link. Those are getting really annoying

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Explanation:

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3 years ago

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LenKa [72]

Answer:

Explanation: 15

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3 years ago

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3 years ago

Read 2 more answers

A piece of unknown metal weighs 348g. When the metal piece absorbs 6.64kj of heat , its temperature increases from 24.4C to 43.6

Morgarella [4.7K]

Answer:

This metal could be the aluminium with a specific heat of $H = 993 \frac{J}{kgC}$

Explanation:

A pie of unknown metal presents a mass (M) of 348 g. This metal is heated using energy (E) of 6.64 kJ and the temperature increases from T1 =24.4 to T2 =43.6°C. We can calculate the specific heat (H) of this metal as follows

$H = \frac{E}{M*(T2-T1)}$

We can replace previously presented data in this equation. After simplifying and converting to adequated units, we found that

$H = \frac{6640 J}{0.348 Kg*(43.6-24.4) C} =\frac{6640 J}{6.686 KgC}$

Finally, the specific heat of this metal is

$H = 993 \frac{J}{kgC}$

The aluminium could be the metal, its specific heat is similar to that found in this problem.

Finally, we can conclude that this metal could be the aluminium with a specific heat of $H = 993 \frac{J}{kgC}$

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Sonja [21]

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2 years ago