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Makovka662 [10]
3 years ago
5

If a 0.7 M solution of Ca(OH)2 dissociates completely in water, what is the final [OH-]?

Chemistry
1 answer:
IceJOKER [234]3 years ago
3 0

Answer:

1.40 M [OH⁻]

Explanation:

This compound dissociates into 3 ions, but since we are asked about [OH⁻], it's only 2. Therefore, multiply the molarity of the solution by the number of ions that [OH⁻] dissociates into:

2 × 0.70 M = 1.40 M

Hope this helps! Sorry that you got a link. Those are getting really annoying

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<u><em>Answer:</em></u>

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3 years ago
how many grams of nahco3 (fm84.007) must be added ro 4.00g of k2co3 (fm 138.206) to give a ph of 10.80 in 500ml of water​
Anna11 [10]

Answer:

0.804g of NaHCO₃ you must add

Explanation:

pKa of HCO₃⁻/CO₃²⁻ is 10.32.

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pH = pka + log [A⁻] / [HA]

<em>Where [HA] is concentration of acid (HCO₃⁻) and [A⁻] is concentration of conjugate acid (CO₃²⁻).</em>

Moles of CO₃²⁻ = K₂CO₃ are:

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0.009570 moles ₓ (84.007g / mol) =

<h3>0.804g of NaHCO₃ you must add</h3>

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2 years ago
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