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MAXImum [283]
3 years ago
7

In a painting, The Great Pyramid of Giza is 45 centimeters tall.

Mathematics
1 answer:
777dan777 [17]3 years ago
6 0

Answer:

The scale is: 1 cm = 3.26 meter

Step-by-step explanation:

Given

Height of Pyramid in Painting = H_p = 45 cm

Actual Height of Pyramid = H_a = 146.5m

In order to find the scale, we can find the ratio between actual height and height in painting.

The ratio can be found by dividing the actual height by height in painting

Scale = \frac{H_a}{H_p}\\= \frac{146.5}{45}\\=3.25555 m/cm

Rounding off to nearest hundredth

= 3.26

This means that the scale is:

1 cm = 3.26 meter

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Divide the amount you need to invest by the percentage.

430/0.05 = 8,600

You earned $8,600

4 0
3 years ago
Please help me answer question B!
skelet666 [1.2K]

Answer:

  • The program counter holds the memory address of the next instruction to be fetched from memory
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  • The accumulator holds the result of any logic or arithmetic operation

Step-by-step explanation:

The specific contents of any of these registers at any point in time <em>depends on the architecture of the computer</em>. If we make the assumption that the only interface registers connected to memory are the memory address register (MAR) and the memory data register (MDR), then <em>all memory transfers of any kind</em> will use both of these registers.

For execution of the instructions at addresses 01 through 03, the sequence of operations may go like this.

1. (Somehow) The program counter (PC) is set to 01.

2. The contents of the PC are copied to the MAR.

3. A Memory Read operation is performed, and the contents of memory at address 01 are copied to the MDR. (Contents are the LDA #11 instruction.)

4. The MDR contents are decoded (possibly after being transferred to an instruction register), and the value 11 is placed in the Accumulator.

5. The PC is incremented to 02.

6. The contents of the PC are copied to the MAR.

7. A Memory Read operation is performed, and the contents of memory at address 02 are copied to the MDR. (Contents are the SUB 05 instruction.)

8. The MDR contents are decoded and the value 05 is placed in the MAR.

9. A Memory Read operation is performed and the contents of memory at address 05 are copied to the MDR. (Contents are the value 3.)

10. The Accumulator contents are replaced by the difference of the previous contents (11) and the value in the MDR (3). The accumulator now holds the value 11 -3 = 8.

11. The PC is incremented to 03.

12. The contents of the PC are copied to the MAR.

13. A Memory Read operation is performed, and the contents of memory at address 03 are copied to the MDR. (Contents are the STO 06 instruction.)

14. The MDR contents are decoded and the value 06 is placed in the MAR.

15. The Accumulator value is placed in the MDR, and a Memory Write operation is performed. Memory address 06 now holds the value 8.

16. The PC is incremented to 04.

17. Instruction fetch and decoding continues. This program will go "off into the weeds", since there is no Halt instruction. Results are unpredictable.

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Note that decoding an instruction may result in several different data transfers and/or memory and/or arithmetic operations. All of this is usually completed before the next instruction is fetched.

In modern computers, memory contents may be fetched on the speculation that they will be used. Adjustments need to be made if the program makes a jump or if executing an instruction alters the data that was prefetched.

4 0
3 years ago
A garden table and a bench cost $950 combined. The garden table costs $50 more than the bench. What is the cost of the bench?
snow_lady [41]
950 - 50 = 900
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The bench cost $450 and the garden table cost $500
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Hope this helps!

3 0
3 years ago
Read 2 more answers
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12345 [234]
Just use the formula:
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c. same as A, not

D. you are already buying one


B and D
8 0
3 years ago
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