The distance between two protons to generate 950N of force is 0.49 X 10⁻¹⁵ m
<u>Explanation:</u>
Given:
Mass of man, m = 100 kg
Force between man and earth = 980 N
Charge of proton, q = 1.6 X 10⁻¹⁹C
Same force is generated between them
Distance between two protons, r = ?
According to Coulomb's law:
where,
k is Coulomb's constant
k = 9 X 10⁹ Nm²/C²
According to the question:
Solving the equation:
Therefore, the distance between two protons to generate 950N of force is 0.49 X 10⁻¹⁵ m
The velocity of the red cart after the collision is 2 m/s
From the law of conservation of momentum, initial momentum of system = final momentum of system.
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.
Substituting the values of the variables into the equation, we have,
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄
4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s
16 kgm/s + 0 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s - 8 kgm/s = (4 kg)v₃
(4 kg)v₃ = 8 kgm/s
Divide both sides by 4 kg, we have
v₃ = 8 kgm/s ÷ 4 kg
v₃ = 2 m/s
The velocity of the red cart after the collision is 2 m/s.
Learn more about conservation of momentum here:
brainly.com/question/7538238
Higher the pressure the air would spread apart causing the paper to move to the other side. So higher pressure causes the papers to move farther apart.