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Alexxx [7]
3 years ago
11

.

Physics
2 answers:
weeeeeb [17]3 years ago
6 0

Answer:

Lower pressure causes the papers to move closer to each other.

Explanation:

As we know by Bernoulli's principle

P + \frac{1}{2}\rho v^2 = constant

so here when air between the two papers is at normal situation then let say the pressure between the two papers is P_o

now if the air between two papers is blown by straw then the speed of air between two papers will increase.

So as per the equation above the pressure will decrease as the sum of pressure and kinetic energy per unit volume must be constant.

So here the pressure between two papers will decrease due to which the two papers will come closer to each other.

so correct answer will be

Lower pressure causes the papers to move closer to each other.

guajiro [1.7K]3 years ago
4 0
Higher the pressure the air would spread apart causing the paper to move to the other side. So higher pressure causes the papers to move farther apart.
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3 years ago
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Residential building codes typically require the use of 12-gauge copper wire (diameter 0.205 cm) for wiring receptacles. Such ci
Alecsey [184]

Given Information:  

Current = I = 20 A

Diameter = d = 0.205 cm = 0.00205 m

Length of wire = L = 1 m

Required Information:  

Energy produced = P = ?

Answer:  

P = 2.03 J/s

Explanation:  

We know that power required in a wire is

P = I²R

and R = ρL/A

Where ρ is the resistivity of the copper wire 1.68x10⁻⁸ Ω.m

L is the length of the wire and A is the area of the cross-section and is given by

A = πr²

A = π(d/2)²

A = π(0.00205/2)²

A = 3.3x10⁻⁶ m²

R = ρL/A

R = 1.68x10⁻⁸*(1)/3.3x10⁻⁶

R = 5.09x10⁻³ Ω

P = I²R

P = (20)²*5.09x10⁻³

P = 2.03 Watts or P = 2.03 J/s

Therefore, 2.03 J/s of energy is produced in 1.00 m of 12-gauge copper wire carrying a current of 20 A

8 0
3 years ago
What is the difference between mutual flux, leakage flux and magnetizing flux<br> ​
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In simple words, flux can be stated as the rate of flow of a fluid, radiant energy, or particles across a given area.

<u>Explanation:</u>

<u>Mutual Flux:</u>

  • The magnetic lines present in among two magnets or solenoid is mutual flux.
  • These are the lines in which the attraction and repulsion happens.
  • The SI unit of mutual flux is the Henry

<u>Leakage Flux:</u>

  • In simple words, it can be stated as  the magnetic flux which does not follow the specially designed way in a magnetic circuit.
  • Leakage flux in the induction motor takes spot due to current runs through the essence of the induction motor.
  • The SI unit of Leakage flux is the Weber

<u>Magnetizing flux</u>

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3 0
3 years ago
A rigid, nonconducting tank with a volume of 4 m3 is divided into two unequal parts by a thin membrane. One side of the membrane
kondor19780726 [428]

The final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.

To find the answer, we need to know about the thermodynamic processes.

<h3>How to find the final temperature of the gas?</h3>
  • Any processes which produce change in the thermodynamic coordinates of a system is called thermodynamic processes.
  • In the question, it is given that, the tank is rigid and non-conducting, thus, dQ=0.
  • The membrane is raptured without applying any external force, thus, dW=0.
  • We have the first law of thermodynamic expression as,

                                dU=dQ-dW

  • Here it is zero.

                                  dU=0,

  • As we know that,

                             dU=C_pdT=0\\\\thus,  dT=0\\\\or , T=constant\\\\i.e, T_1=T_2

  • Thus, the final temperature of the system will be equal to the initial temperature,

                          T_1=T_2=100^0C=373K

<h3>How much work is done?</h3>
  • We found that the process is isothermal,
  • Thus, the work done will be,

                               W=RT*ln(\frac{V_2}{V_1} )=373R*ln(\frac{4}{\frac{4}{3} })\\ \\W=409.8R J

Where, R is the universal gas constant.

<h3>What is a reversible process?</h3>
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Thus, we can conclude that, the final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.

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Answer:

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when n = 15

1/λ = 1.097 × 10⁷ m⁻¹(1/2² -1/15²)

    = 1.097 × 10⁷ m⁻¹(1/4 -1/225)

    = 1.097 × 10⁷ m⁻¹(0.25 - 0.0044)

    = 1.097 × 10⁷ m⁻¹ 0.245556

    = 2.693 10⁶ m⁻¹

So,

λ  = 1/2.693 10⁶ m⁻¹

    = 0.3712 10⁻⁶ m

    = 371.2 mm

7 0
3 years ago
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