Question

A ball is projected at an angle of 30° above the horizontal with a speed of 35 m/s. What will be its approximate horizontal range across a level surface?

Answer 1

37.5 m  will be its approximate horizontal range across a level surface.

we have given in the data

u (initial velocity) = 35 m/s

projected  angle = 30°

Horizontal range =?

range of horizontal distance$=\frac{u^2 Sin 2 \theta}g$

PUTTING all the values in the equation

horizontal range= $\frac{35\cdot35\cdot sin60}{9.8}$

by solving, we got

horizontal range=37.5 m

• The horizontal distance traversed is the projectile's range,The thing moves in one direction until it hits the ground.
• When an item is hurled at an angle of 90°, only vertical motion occurs. As a result, the projectile's range will be zero.
• horizontal range variates with angle, initial velocity, and by the value of g.

To know more about  horizontal range visit : brainly.com/question/23827445

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