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KIM [24]
3 years ago
11

Where do you think the government should put the greatest support: solar energy, wind energy, clean coal, oil exploration, gas e

xploration, or a combination of sources? Are there other efforts that should be explored?
Physics
2 answers:
True [87]3 years ago
7 0
The government should put it support in a combination of sources, as no source in the present can fully provide all energy requirements.
telo118 [61]3 years ago
5 0

Answer:

I believe that the government should focus on supporting solar and wind energy over anything else.

Explanation:

There are two reasons why I believe the government should put the greatest efforts in solar and wind energy.

First of all, obtaining coal, natural gas, and oil is cheap because the governments and companies have put great amounts of money in research to produce it at the lowest possible costs. Therefore if we fund research with the same model, we are going to obtain cheaper costs. The second reason is that they are renewable and 0 pollution sources of energy, unlike coal, gas, and il. Also, we can create engines like the ones electric cars use, to all transports.

There are other efforts like nitrogen, geothermic energy and my favorites, gravitational rejection impulse energy and electromagnetic energy like the one the Japanese shinkansen uses.

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PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Leya [2.2K]

Answer:

c

Explanation:

5 0
2 years ago
ASAP need physics help please:)
boyakko [2]

Answer:

plantation of force of the earth acting on 15 kg of object on free fall the acceleration of free fall said about it now it is year 15 kg then it becomes 1.53 Newton

3 0
2 years ago
Assume the earth to be a nonrotating sphere with mass MEME and radius RERE. If an astronaut weights WW on the ground, what is hi
Solnce55 [7]

Answer:

The weight at a distance 2 RE from surface of earth is <em>W/9</em>

Explanation:

For the value of acceleration due to gravity (g), we have a formula, that is:

g = (G)(ME)/(RE)²    ----- equation (1)

where,

G = Gravitational Constant

ME = Mass of Earth

RE = Radius of Earth

g = Acceleration due to gravity on surface of earth = 9.8 ms²

When the person goes 2RE, distance above earth's surface. Then the total distance from center of earth becomes: 2RE + RE = 3RE.

Therefore, equation (1) becomes:

gh = (G)(ME)/(3RE)²

where,

gh = acceleration due to gravity at height

gh = (G)(ME)/(RE)²9

using equation (1), we get:

gh = g/9

Now, he weight is given by formula:

W = mg   ------- equation (2)

At height 2RE

Wh = (m)(gh)

where,

Wh = Weight at height = ?

m = mass of astronaut

Therefore, using vale of gh, we get:

Wh = mg/9

Using equation (2), we get:

<u>Wh = W/9</u>

6 0
3 years ago
Sully uses a battery and a coil of wire to create an electromagnet. Using the same materials, if he wants to increase the streng
garik1379 [7]
An electromagnet is a type of magnet in which the magnetic field is produced using the current. The simplest form of an electromagnet is a wire wrapped around in a coil.
The strength of magnetic field of such magnet is given with this equation:
B=\frac{NI\mu}{L}
Where N is the number of loops in the coil, I is the strength of the current flowing through the coil, L is the length of the coil, and \mu is <span>permeability of the electromagnet core material.
From this equation, we can see that increasing both the current and number of loops will increase the strength of the magnet.
Both BLANKS should be Increase. When you use the additional battery you will have more voltage and more voltage means more electricity.</span>
5 0
3 years ago
Why is the motion of an athlete moving along the circular path with Constant speed considered to be an accelerated motion?
Strike441 [17]

The speed is changing its direction all the time. There is an acceleration which changes the direction of the speed – that is called centripetal acceleration. Only uniform linear motions are considered to have no acceleration.

This is the general formula for acceleration

a = dv/dt

When calculating dv, you should keep in mind the change in the velocity vector’s direction. You can easily see in a graph that with dt tending to 0 (so the length of the arc covered is also tending to 0), the difference between vectors Vf and V0 has a direction which is perpendicular to velocity (the shorter the arc, the closest the angle is to 90 degrees).

There is a formula (which can be deducted from the previous formula) which allows you to calculate the acceleration:

a = v^2/r

Let’s talk about the units:

v is in m/s

r is in m

so v^2/r

is in (m/s)^2/m = (m^2/s^2)/m = m/s^2

which is the same unit as dv/dt:

dv/dt = (m/s)/s= m/s^2

5 0
3 years ago
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