Answer:
88.5 % of the raw ore is CuSO4*4H2O
Explanation:
Step 1: Data given
Mass of the ore = 10.854 grams
Mass of water = 2.994 grams
Step 2: Calculate moles H2O
Moles H2O = mass H2O / molar mass H2O
Moles H2O = 2.994 grams / 18.02 g/mol
Moles H2O = 0.166 moles
Step 3: Calculate moles CuSO4*4H2O
For 1 mol CuSO4*4H2O we have 4 moles H2O
For 0.166 moles H2O we have 0.166/4 = 0.0415 moles CuSO4*4H2O
Step 4: Calculate mass CuSO4*4H2O
Mass CuSO4*4H2O = moles * molar mass
Mass CusO4*4H2O = 0.0415 moles * 231.67 g/mol
Mass CuSO4*4H2O = 9.61 grams
Step 5: Calculate mass % of CuSO4*4H2O
Mass % = (9.61 grams / 10.854 grams )*100 %
Mass % = 88.5 %
88.5 % of the raw ore is CuSO4*4H2O
