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Contact [7]
3 years ago
15

The pressure of a gas produces a net force (the sum of all the forces) at ____ angles to the wall of a container.

Physics
1 answer:
ivanzaharov [21]3 years ago
7 0

Answer: RIGHT angles

Explanation:

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The resistivity of a semiconductor can be modified by adding different amounts of impurities. A rod of semiconducting material o
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pp

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3 years ago
Find the magnitude of the sum
shusha [124]

Answer:

\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m

Explanation:

<u>Sum of Vectors in the Plane</u>

Given two vectors

\displaystyle \vec{v_1}\ ,\ \vec{v_2}

They can be expressed in their rectangular components as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_2}=

The sum of both vectors can be done by adding individually its components

\displaystyle \vec{v_1}+\vec{v_2}=

If the vectors are given as a magnitude and an angle (M\ ,\ \theta ), each component can be found as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_2}=

The first vector has a magnitude of 3.14 m and an angle of 30°, so

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=

The second vector has a magnitude of 2.71 m and an angle of -60°, so

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=

The sum of the vectors is

\displaystyle \vec{v_1}+\vec{v_2}=

\displaystyle \vec{v_1}-\vec{v_2}=

Finally, we compute the magnitude of the sum

\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{(4.08)^2+(-0.78)^2}

\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{17.25}

\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m

3 0
2 years ago
A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.3
shusha [124]

Answer:

a

  x_2 = -2.3356

b

 v = -1.384 \ m/s

Explanation:

From the question we are told that

  The initial position of the particle is  x_1 = 0.180 \ m

  The initial  velocity of the particle is  u = 0.060  \  m/s

  The acceleration is   a = -0.380 \  m/s^2

   The time duration is  t = 3.80  \ s

Generally from kinematic equation

    v = u + at

=>  v = 0.060 + (-0.380 * 3.80)

=>  v = -1.384 \ m/s

Generally from kinematic equation

   v^2 = u^2 + 2as

Here s is the distance covered by the particle, so

   (-1.384)^2 = (0.060)^2 + 2(-0.380)* s

=>  s = -2.5156 \ m

Generally the final position of the particle is  

    x_2 = x_1 + s

=>   x_2 = 0.180 + (-2.5156)

=>   x_2 = -2.3356

6 0
2 years ago
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