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Y_Kistochka [10]
3 years ago
9

1. As elements go across from left to right in a period,

Chemistry
1 answer:
mel-nik [20]3 years ago
7 0

Answer:

decrease.

Explanation:

WHY? - As you go across a period, electrons are added to the same energy level. ... The concentration of more protons in the nucleus creates a "higher effective nuclear charge." In other words, there is a stronger force of attraction pulling the electrons closer to the nucleus resulting in a smaller atomic radius.

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If 5. 0 grams of kcl is dissolved in 500 ml of water, what is the concentration of the resulting solution?
Lady_Fox [76]

If 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.

<h3>How to calculate concentration?</h3>

The concentration of a solution can be calculated by using the following formula;

Molarity = no of moles ÷ volume

According to this question, 5.0 grams of KCl is dissolved in 500 ml of water. The concentration is calculated as follows:

no of moles of KCl = 5g ÷ 74.5g/mol = 0.067mol

Molarity = 0.067mol ÷ 0.5L = 0.134M

Therefore, if 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.

Learn more about concentration at: brainly.com/question/10725862

#SPJ1

6 0
2 years ago
A solution of the ionic salt NaF
vichka [17]
<h3>A. an acidic............</h3>
8 0
3 years ago
A 10 mm Brinell hardness indenter is used for some hardness testing measurements of a steel alloy. a) Compute the HB of this mat
Lady_Fox [76]

Explanation:

(a)  The given data is as follows.  

         Load applied (P) = 1000 kg

         Indentation produced (d) = 2.50 mm

         BHI diameter (D) = 10 mm

Expression for Brinell Hardness is as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}    

Now, putting the given values into the above formula as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}                            = \frac{2 \times 1000 kg}{3.14 \times 10 mm [D - \sqrt{((10 mm)^{2} - (2.50)^{2})}]}  

                       = \frac{2000}{9.98}                          

                       = 200

Therefore, the Brinell HArdness is 200.

(b)     The given data is as follows.

               Brinell Hardness = 300

                Load (P) = 500 kg

               BHI diameter (D) = 10 mm

             Indentation produced (d) = ?

                      d = \sqrt{(D^{2} - [D - \frac{2P}{HB} \pi D]^{2})}

                         = \sqrt{(10 mm)^{2} - [10 mm - \frac{2 \times 500 kg}{300 \times 3.14 \times 10 mm}]^{2}}

                          = 4.46 mm

Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.

5 0
3 years ago
What is evidence when mixing sugar into water
Tems11 [23]
That water is a universal solvent and that sugar is soluble?
3 0
4 years ago
If one body is positively charged and another one is negatively charged free electrons tend to ?
lord [1]

Answer is: Move from the negatively charged body to the positively charged body.

The electron (symbol: e⁻) is a subatomic particle whose electric charge is negative one elementary charge.

The proton (p⁺) is subatomic particle with a positive electric charge of +1e elementary charge.

Opposite charges (positive and negative) attract one another.  

The negatively charged body has extra electrons, more electrons than protons.

The positively charged body has less electrons than protons.

5 0
4 years ago
Read 2 more answers
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