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Y_Kistochka [10]
3 years ago
9

1. As elements go across from left to right in a period,

Chemistry
1 answer:
mel-nik [20]3 years ago
7 0

Answer:

decrease.

Explanation:

WHY? - As you go across a period, electrons are added to the same energy level. ... The concentration of more protons in the nucleus creates a "higher effective nuclear charge." In other words, there is a stronger force of attraction pulling the electrons closer to the nucleus resulting in a smaller atomic radius.

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Which transition metals are in pale pink paint?
vova2212 [387]
The metallic elements located anywhere between 3-12 of the periodic table
5 0
3 years ago
Codeine C18H21NO3 is a weak organic base. A 5.0 x 10^-3 M solution of codeine has a pH of 9.95. Calculate the value of Kb for th
arsen [322]

Answer:

Kb = 4.45\times10^{-7}\ mol/L

p^{Kb}=6.35

Explanation:

For a weak organic base, the formula to find p^{OH} is given by:

p^{OH}=p^{K_b}+\log c

where c is the concentration of base.

Here c= 5\times10^{-3}\ M

p^{H}=9.95\\p^{OH}=14-p^{H}=14-9.95=4.05

Substituting the above values in the formula,we get:

p^{k_b}=p^{OH}-\log c\\p^{k_b}=4.05-\log (5\times10^{-3})\\p^{K_b}=6.35\\K_b=$antilog 6.35=4.45\times10^{-7}\ mol/L

Hence:

Kb = 4.45\times10^{-7}\ mol/L

p^{Kb}=6.35

7 0
3 years ago
Consider this hydrocarbon. A hexagon. Is this an aromatic hydrocarbon? Why or why not? Yes, because the carbon chain is made up
grin007 [14]

Answer:

C. No, because the carbon chain is composed of only a single ring.

Polycyclicity, having more than a single ring, is a property of only aromatic hydrocarbons. Therefore, if the hydrocarbon is not polycyclic, it is non-aromatic

Explanation:

Cyclic Hydrocarbons

These are organic compounds which are cyclic in structure. The compound cyclohexane involves a ring of six carbon atoms, each of which is also bonded to two hydrogen atoms

Aromatic hydrocarbons are cyclic ring organic compound which are based on the benzene ring structure.

A. If the hexagon contains single bonds, it is non-aromatic.

B. No. Having a ring shape does not on its own determine the aromaticity of a hydrocarbon.

C. Polycyclicity, having more than a single ring, is a property of only aromatic hydrocarbons. Therefore, if the hydrocarbon is not polycyclic, it is non-aromatic

D. Having double bonds within a ring is not a criteria for being aromatic. Both aromatic and non-aromatic hydrocarbons have double bonds within their rings. However, aromatic hydrocarbons have alternate double and single bonds within their 6-carbon ring structure.

Note: Since the structure of the required hydrocarbon is not shown, the explanation contains attachments of hexagonal structures of three hydrocarbons; one non-aromatic and the other two are aromatic. Cyclohexane is non-aromatic while Benzene and the polycyclic compounds are aromatic.

7 0
3 years ago
A series of experiments investigating the reaction of (CH3)3CCl with H2O to create (CH3)3OH produces a plot of Ln[(CH3)3CCl] vs.
Helga [31]

Explanation:

There will occur a straight line for the curve of Ln[(CH_{3})_{3}CCl] Vs. time. Since, it is a first order reaction therefore, the formula of its half-life will be as follows.

         Half-life = \frac{ln 2}{k}

or,         k = \frac{ln 2}{t_{\frac{1}{2}}}

               = \frac{ln 2}{220} sec^{-1}

So, rate of the reaction will be as follows.

          Rate = [(CH_{3})_{3}CCl]^{1}

                   = \frac{ln 2}{220} sec^{-1} \times 0.15 M

                   = 0.000473 Ms^{-1}

                   = 4.73 \times 10^{-4} Ms^{-1}

Thus, we can conclude that the instantaneous rate of given reaction is  4.73 \times 10^{-4} Ms^{-1}.

3 0
3 years ago
How to find the atomic number of an element
irinina [24]
The little number at the top of the element

6 0
2 years ago
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