All categories

3 years ago

1. As elements go across from left to right in a period,

Chemistry

1 answer:

mel-nik [20]3 years ago

7 0

Answer:

decrease.

Explanation:

WHY? - As you go across a period, electrons are added to the same energy level. ... The concentration of more protons in the nucleus creates a "higher effective nuclear charge." In other words, there is a stronger force of attraction pulling the electrons closer to the nucleus resulting in a smaller atomic radius.

You might be interested in

Please help me like now please

777dan777 [17]

Answer:

1-1) NaHCO3 + CH3COOH --> NaCH3COO + H2O + CO2

1-2) 0.5 mole of CO2

2-1) 2C4H10 + 13O2 --> 8CO2 + 10H2O

2-2) 4 mol CO2

Explanation:

Question 1

NaHCO3 + CH3COOH --> NaCH3COO + H2O + CO2

To balance the equation, count the number of atoms on both sides of the equation

(1 Na, 1+3+1H, 1+1+1C, 3+2Oxygen) --> (1 Na, 1+1+1C, 3+2H, 2+1+2Oxygen)

Combining the pluses will give you the following

(1 Na, 5H, 3C, 5Oxygen) --> (1 Na, 3C, 5H, 5Oxygen)

Both sides are the same, therefore the chemical equation is balanced (originally).

From the equation, we can see that 1 mole of NaHCO3 produces 1 mole of CO2.

So that means 0.5 mole of NaHCO3 would produce 0.5 mole of CO2.

Question 2

C4H10 + O2 --> CO2 + H2O

Again, count the number of atoms on both sides of the equation

(4C, 10H, 2O) --> (1C, 2H, 3O) This time left does not equal right side

You now need to find factors that can make both sides equal.

C4H10 + O2 --> 4CO2 + H2O Now the C is balanced, let's recount 

(4C, 10H, 2Oxygen) --> (4C, 8+1Oxygen, 2H) H&O is still not balanced

C4H10 + O2 --> 4CO2 + 5H2O Now the H is balanced, let's recount

(4C, 10H, 2Oxygen) --> (4C, 8+5Oxygen, 10H) O is still not balanced

C4H10 + (13/2)O2 --> 4CO2 + 5H2O Now the O is balanced

(4C, 10H, 13Oxygen) --> (4C, 13Oxygen, 10H)

But because 13/2 is a fraction, we want to eliminate that by multiplying every reactant and product by 2 (the denominator).

2C4H10 + 13O2 --> 8CO2 + 10H2O Now it's completely balanced!

(8C, 20H, 28Oxygen) --> (8C, 28Oxygen, 20H) Yayy! It's balanced.

Now, 2 mol C4H10 produces 8 mol CO2.

So 1 mol C4H10 produces 4 mol CO2.

6 0

2 years ago

Answer ASAP!!!

eduard

Answer:

Yes, you heard right!" she wrote for the news outlet. "Using your partner's sperm as a mask is full of a compound called spermine, which is an antioxidant which can help reduce wrinkles, smooth the skin, prevent acne or spots and give you overall healthy-looking skin.

And yes they do have st home sperm freezing kits you can order

good luck

7 0

3 years ago

Determine the molar mass of a compound that has a density of 0.1633 g/L at STP. (show work)

hodyreva [135]

Answer:

M.Mass = 3.66 g/mol

Data Given:

M.Mass = M = ??

Density = d = 0.1633 g/L

Temperature = T = 273.15 K (Standard)

Pressure = P = 1 atm (standard)

Solution:

Let us suppose that the gas is an ideal gas. Therefore, we will apply Ideal Gas equation i.e.

P V = n R T ---- (1)

Also, we know that;

Moles = n = mass / M.Mass

Or, n = m / M

Substituting n in Eq. 1.

P V = m/M R T --- (2)

Rearranging Eq.2 i.e.

P M = m/V R T --- (3)

As,

Mass / Volume = m/V = Density = d

So, Eq. 3 can be written as,

P M = d R T

Solving for M.Mass i.e.

M = d R T / P

Putting values,

M = 0.1633 g/L × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K / 1 atm

M = 3.66 g/mol

6 0

2 years ago

Which vein carries oxygenated blood back into the heart?

Finger [1]

Answer:

The veins that carry oxygenated bloof back into the heart are the pulmonary arteries.

Explanation:

Oxygen-rich blood flows from the lungs back into the left atrium (LA), or the left upper chamber of the heart, through four pulmonary veins. Oxygen-rich blood then flows through the mitral valve (MV) into the left ventricle (LV), or the left lower chamber.

6 0

2 years ago

Read 2 more answers

Срочно!!!!!!!помогите пожалуйста

Marizza181 [45]

Answer:

bsnsjwjjwjwjw

Explanation:

bsbsbsnsnsnsjs

8 0

3 years ago

Read 2 more answers