Answer:
The first blank: 65
The second blank: 24
The third blank: 16
The last blank is: 41
Step-by-step explanation:
The Phthagorean theorm is as follows: c^2=a^2+b^2
Where a and b are the legs of the triangle and c is the hypotenuse
To fill in the first blank space you need to find c, and it's given a and b: a=25 b=60
You substitute the known values into the equation of the Pythagorean theorm: c^2=25^2+60^2
And solve to find c
c^2=4225
c=
c=65
The answer for the first blank
For the second blank you given a and c: a=7 c=25
Substitute the value into Pythagorean theorm:c^2=a^2+b^2
25^5=7^2+b^2
625=49+b^2
To solve b you got to subtract 49 to both sides
625-49=b^2
576=b^2
24=b
Which is your answer
For the third blank its given b and c: b=30 c=34
Substitute the value into Pythagorean theorm
c^2=a^2+b^2
34^2=a^2+30^2
Solve the exponential terms: 1156=a^2+900
Then you solve the variable that you need to find. In this case, you got to solve a^2 by subtracting 900 of both sides of the equation:1156-900=a^2
256=a^2
16=a which is your answer
Finally your last blank,its given the values and b
a=9
b=40
Substitute the value into Pythagorean theorm
c^2=9^2+40^2
And solve for c
c^2=81+1600
c^2=1681
Which gives you c=41 which is your answer
Let me know if this helps
Answer:
First, plug-in x and y as 3sinθ-2 and 3cosθ+4 into the equation, respectively:
Then, +2 and -2 cancel out and +4 and -4 cancel out as well, leaving you with:
We can factor out 3^2 = 9 from both equations:
We know from a trigonometric identity that , meaning we can reduce the equation to:
And therefore, we have shown that (x+2)^2 + (y-4)^2 = 9, if x=3sinθ-2 and y=3cosθ+4.
Hope this helped you.
Given:
The vertices of a polygon QRST are T(-2, 3), Q(1, 5), R(3, -1) and S(0, 0).
To find:
The vertices for .
Solution:
The rule represents refection of polygon QRST across the x-axis.
If a figure is reflected across the x-axis, then
Using this rule, we get
Therefore, the vertices for are T'(-2, -3), Q'(1, -5), R'(3, 1) and S'(0, 0).