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True [87]
3 years ago
7

HHHHHHHHHEEEEEEEEEELLLLLLLLLLPPPPPPPPP ILL FAIL MY CLASSSSSSSSSSSSSS

Mathematics
2 answers:
erica [24]3 years ago
7 0

Answer:

The first blank: 65

The second blank: 24

The third blank: 16

The last blank is: 41

Step-by-step explanation:

The Phthagorean theorm is as follows: c^2=a^2+b^2

Where a and b are the legs of the triangle and c is the hypotenuse

To fill in the first blank space you need to find c, and it's given a and b: a=25 b=60

You substitute the known values into the equation of the Pythagorean theorm: c^2=25^2+60^2

And solve to find c

c^2=4225

c=

\sqrt{4225}

c=65

The answer for the first blank

For the second blank you given a and c: a=7 c=25

Substitute the value into Pythagorean theorm:c^2=a^2+b^2

25^5=7^2+b^2

625=49+b^2

To solve b you got to subtract 49 to both sides

625-49=b^2

576=b^2

\sqrt{576}  = b

24=b

Which is your answer

For the third blank its given b and c: b=30 c=34

Substitute the value into Pythagorean theorm

c^2=a^2+b^2

34^2=a^2+30^2

Solve the exponential terms: 1156=a^2+900

Then you solve the variable that you need to find. In this case, you got to solve a^2 by subtracting 900 of both sides of the equation:1156-900=a^2

256=a^2

\sqrt{256 = a}

16=a which is your answer

Finally your last blank,its given the values and b

a=9

b=40

Substitute the value into Pythagorean theorm

c^2=9^2+40^2

And solve for c

c^2=81+1600

c^2=1681

c =  \sqrt{1681}

Which gives you c=41 which is your answer

Let me know if this helps

timurjin [86]3 years ago
3 0

Answer:

c is the right answer of this

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Answer:

(a) The value of <em>x</em> is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.

Step-by-step explanation:

Denote the events as follows:

<em>R</em> = reported case of rabies is a raccoon

<em>F</em> = reported case of rabies is a fox

<em>B</em> = reported case of rabies is a bat

<em>O</em> = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = <em>x</em>.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, \sum P(X)=1

Compute the value of <em>x</em> as follows:

\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30

Thus, the value of <em>x</em> is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

P(A^{c})=1-P(A)

Compute the probability that a reported case of rabies is not a raccoon as follows:

P(R^{c})=1-P(R)\\=1-0.55\\=0.45

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

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