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3 years ago

Which fats result when manufacturers add hydrogen to fat molecules in vegetable oil?

Chemistry

2 answers:

IrinaVladis [17]3 years ago

8 0

Answer:

The correct answer is trans-fat.

Explanation:

The trans-unsaturated fatty acids or trans fat is a kind of unsaturated fat, which takes place in small concentrations in nature, however, it became broadly generated industrially from vegetable fats beginning in the 1950s for the application in snack food, margarine, and others.

The fats constitute long chains of hydrocarbons that can be either saturated or unsaturated. In food production, liquid cis-unsaturated fats like vegetable oils are hydrogenated to generate saturated fats that exhibit more desirable physical characteristics.

VladimirAG [237]3 years ago

7 0

The type of fat that is described above is the trans fat. The trans fat is artificially made and these fat contains partially hydrogenated oils which is similar to the statement above. The reason why they are added to oil like vegetable oils so that there property could become solid.

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What is the instantaneous rate of formation of product C given the following information: a. Stoichiometric equation A+ B2C+ D b

quester [9]

Answer:

1.728 mol /(L*min)

Explanation:

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3 years ago

You measure the absorbance of your extracted curcumin solution and realize that the solution is too concentrated. What made you

zepelin [54]

If the absorbance of a solution of curcumin which is too concentrated is measured, the absorbance will be unusually high.

Spectrometry measures the interaction of light with molecules. The absorbance refers to how much light that interacts with molecules of the substance. The more the concentration of the substance the higher the absorbance of the solution.

Hence, if the absorbance of a solution of curcumin which is too concentrated is measured, the absorbance will be unusually high. An unusually high absorbance tells us that the solution is too concentrated.

Learn more: brainly.com/question/13440572

8 0

2 years ago

Which of the following statements is true?

Lera25 [3.4K]

The statement which is true is

metals lose electrons to become cations

<u><em>Explanation</em></u>

metals tends to loss electrons to attain noble gas electrons configuration.
When metal loses electrons they form a positive charged ions.
The positively charged ion is known as cations.
for example sodium metal (Na) loses 1 electron to form a cation with a charge of positive 1 ( Na^+)

3 0

3 years ago

Read 2 more answers

What are the chemical properties of beryllium phosphide??

o-na [289]

Answer:

Forms ionic bonds, insoluble, doesn't participate in single or double displacement reactions, non-reactive, high heat of combustion

Explanation:

Beryllium is a metal, since it belongs to group 2A, the alkaline earth metals. It has a total of 2 valence electrons.

Phosphorus, on the other hand, belongs to group 5A and has a total of 5 valence electrons.

We have a compound which has a metal in it, therefore, it's an ionic compound. Beryllium, our metal, loses its 2 electrons to gain an octet and phosphorus, our nonmetal, should gain 3 electrons to have an octet. The oxidation states are +2 and -3 respectively. This means we need 3 beryllium cations and 2 phosphide anions in our formula $Be_3P_2$ .

Beryllium phosphide would be expected to be insoluble, as only beryllium chloride, fluoride, nitrate, phosphate and sulfate are soluble substances, while the remaining ones are expected to be insoluble.

Due to its insolubility, beryllium phosphide would not participate in any ionic reactions, such as single displacement or double displacement.

Since it's insoluble, we expect this compound to be chemically stable and not reactive. This implies that if we wanted to burn it, the heat of combustion would be very high, as a lot of energy would be needed to be supplied in an endothermic reaction in order to burn it.

8 0

3 years ago

A sample of bleach was analyzed as in this procedure. The only procedural difference is that the student weighed out the bleach

Bogdan [553]

Answer:

% = 5.69%

Explanation:

To do this, we need to write the equations taking place here. First, this is a REDOX reaction where the hypoclorite and thiosulfate solution reacts. The balanced equations are:

ClO⁻ + 2I⁻ + 2H⁺ -------> Cl⁻ + I₂ + H₂O

I₂ + 2S₂O₃²⁻ -----------> 2I⁻ + S₄O₆²⁻

We already have the required volume and concentration of the thiosulfate solution, so we can calculate the moles of thiosulfate. With this moles, we can calculate the moles of hypochlorite, then the mass and finally the %.

The moles of thiosulfate would be:

moles S₂O₃²⁻ = V * M

moles S₂O₃²⁻ = 0.01324 * 0.0732 = 9.69x10⁻⁴ moles

Now according to the above reactions, we can see that

moles I₂ = moles ClO⁻

and

moles I₂ / moles S₂O₃²⁻ = 1/2

Therefore, let's calculate the moles of ClO⁻:

moles ClO⁻ = 9.69x10⁻⁴ / 2 = 4.845x10⁻⁴ moles

Now, we can calculate the mass of these moles, using the molar mass of sodium hypochlorite which is 74.44 g/mol:

m = 74.44 * 4.845x10⁻⁴

m = 0.036 g

Finally the % of this, in the bleach sample would be:

% = 0.036 / 0.634 * 100

6 0

3 years ago