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2 years ago

Which object will move faster?

Physics

2 answers:

Lynna [10]2 years ago

6 0

Answer:

C: A 3lb box.

Explanation:

If we were taking about something moving on a surface in which case the answer would be C: a 3lb box because it has the smallest mass therefore it would have the smallest friction.

Unless, the question is asking which would fall faster in which case an 18-wheeler will fall a lot faster than the others because it will provide more net force against the air pressure.

It all depends on if the question is asking which would fall faster or if the question was asking which would move the fastest on a surface. I would just say a 3lb box because the question doesn't use the word fall.

Katarina [22]2 years ago

4 0

Answer:

depends on how big the car is and what force is moving them.

Explanation:

the 3lb box will go slower because it is the lightest. the 10lb box is the 2nd slowest. the car will be smaller than the 18 wheeler on the road. but it has less cargo so it will probably go faster. if you are dropping it, then the 18 wheeler will go faster. but if you are seeing if it will go faster on the ground, the car will because it has less cargo or wheels to weigh it down.

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a student pushes a box with a total mass of 50kg. what is the net force on the box if it accelerates 1.5 m/s^2?

Zielflug [23.3K]

F=mass times acceleration so multiple 50 by 1.5 and u get 75

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3 years ago

Jaiden is writing a report about the structure of the atom. In her report, she says that the atom has three main parts and two s

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3 years ago

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What is true of all particles of gas enclosed within a container?

Andre45 [30]

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3 years ago

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A projectile is launched at ground level with an initial speed of 54.5 m/s at an angle of 35.0° above the horizontal. It strikes

Alchen [17]

<h2>Answer: x=125m, y=48.308m</h2>

Explanation:

This situation is a good example of the projectile motion or parabolic motion, in which we have two components: x-component and y-component. Being their main equations to find the position as follows:

x-component:

$x=V_{o}cos\theta t$ (1)

Where:

$V_{o}=54.5m/s$ is the projectile's initial speed

$\theta=35\°$ is the angle

$t=2.80s$ is the time since the projectile is launched until it strikes the target

$x$ is the final horizontal position of the projectile (the value we want to find)

y-component:

$y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0$ is the initial height of the projectile (we are told it was launched at ground level)

$y$ is the final height of the projectile (the value we want to find)

$g=9.8m/s^{2}$ is the acceleration due gravity

Having this clear, let's begin with x (1):

$x=(54.5m/s)cos(35\°)(2.8s)$ (3)

$x=125m$ (4) This is the horizontal final position of the projectile

For y (2):

$y=0+(54.5m/s)sin(35\°)(2.8s)-\frac{(9.8m/s^{2})(2.8s)^{2}}{2}$ (5)

$y=48.308m$ (6) This is the vertical final position of the projectile

4 0

3 years ago

For a 50 kV anode voltage, what is the maximum photon energy of the x-ray radiation?

V125BC [204]

Answer:

The energy of photon, $E=8\times 10^{-15}\ J$

Explanation:

It is given that,

Voltage of anode, $V=50\ kV=50\times 10^3\ V=5\times 10^4\ V$

We need to find the maximum energy of the photon of the x- ray radiation. The energy required to raise an electron through one volt is called electron volt.

$E=eV$

e is charge of electron

$E=1.6\times 10^{-19}\times 5\times 10^4$

$E=8\times 10^{-15}\ J$

So, the maximum energy of the x- ray radiation is $8\times 10^{-15}\ J$ . Hence, this is the required solution.

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3 years ago