Ask question

Ask question

All categories

2 years ago

14

A crate is to be pulled across the floor. The crate will experience a force of friction of 34 N. You pull on the crate with a fo

rce of 75 N. The mass of the crate is 8.5 kg.
What is the net force acting on the crate?

What is the crate's rate of acceleration?

1 answer:

Jobisdone [24]2 years ago

6 0

The net force would be 75N - 34N = 41N

The crates rate of acceleration would be 41N=8.5*a so a = 4.8m/s^2

You might be interested in

Suppose your salary in 2012 is $70,000. Assuming an annual inflation rate of 7%, what salary do you need to earn in 2020 in orde

s2008m [1.1K]

Annual salary(2012) = $70,000

Annual inflation = 7%

Therefore, the salary you need to earn in 2020 in order to have the same purchasing power can be calculated below

$2020-2012=8\text{ years}$ $FV=PV\times(1+r)^n$

where

n = 8

r = 7/100 = 0.07

PV = 70, 000

$\begin{gathered} FV=70,000(1+0.07)^8 \\ FV=70000(1.07)^8 \\ FV\text{ = 70000}\times1.71818617983 \\ FV=120273.032588 \\ FV=\text{ \$}120,273.03 \end{gathered}$

The salary you need to earn in 2020 to have the same purchasing power = $120, 273.03

8 0

10 months ago

How much force is applied if a 130kg mass is accelerated at 5 m/s^2?

STALIN [3.7K]

Answer:

650N

Explanation:

f= ma

130kg x 5 m/s^2 = 650N

5 0

2 years ago

Just before the ball leaves her hand, what is its centripetal acceleration?

erica [24]

A = $\frac{ v^{2} }{r}$ = ω²r

5 0

2 years ago

Help with this question please :>

zheka24 [161]

Answer: A if thats not right its C

Explanation:

3 0

2 years ago

Read 2 more answers

suppose you use three different scales to weigh bag of oranges one scale says the bag weighs 2.1 lbs a second says it weighs 2.2

Ber [7]

Answer:

It would be 2.2 if you have to round the five to the one but if your not rounding the number, it'd be 2.1.

Explanation:

4 0

2 years ago