Answer:
<h2>1. Find the dot product of the vectors.</h2>
<h2>2. Divide the dot product with the magnitude of the first vector.</h2><h2 /><h2>3. Divide the resultant with the magnitude of the second vector.</h2>
Answer:kmjn npjnmomiomoipjmoi;
m[oko
Explanation:
kmn[oimj;nmpin; k;lm'm[ion[oin[oi
The portion of the flux leaves the curved surface of the cylinder is 60%.
<h3 /><h3>What are electrons?</h3>
The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.
If a point charge is located at the center of a cylinder and the electric flux leaving one end of the cylinder is 20% of the total flux leaving the cylinder.
If 20% of the flux leave from one end, then another 20% will leave from another end.
So, the net flux through curved surface is
100 -20 -20 = 60%
Thus, the total flux leaves the curved surface of the cylinder is 60%
Learn more about electrons.
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Answer:
Both the Technician A and Technician B are correct
Explanation:
According to Technician A, an ammeter measures current flow which is correct.
An ammeter is a device which measures the rate of flow of electrons constituting electric current that flows in a circuit.
According to Technician B, Ammeter must be connected in series in an electric circuit which is also correct.
In a circuit with parallel connections, voltage across each branch is same and current is distributed and is different in each branch.
In a series connected circuit, the potential drop, i.e., voltage across each connected element is different while the current in series is the same.
So, in order to measure the correct value of current flowing in the circuit, ammeter must be connected in series in the circuit.
<h3>
Answer:</h3>
2.5 mg
<h3>
Explanation:</h3>
<u>We are given</u>;
- Original mass of I-131 is 40.0 mg
- Half life of I-131 is 8 days
- Number of days 32 days
We are required to determine the mass that will remain;
N = N₀ × 0.5^n
where, N is the remaining mass, N₀ is the original mass, and n is the number of half lives.
Therefore;
n = time ÷ half life
= 32 days ÷ 8 days
= 4
Therefore;
Remaining mass = 40.0 mg × 0.5^4
= 2.5 mg
Hence, the remaining mass of I-131 after 32 days is 2.5 mg