High tide or Neap tides which are normally really high.
Answer:
50 g of K₂CO₃ are needed
Explanation:
How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?
We analyse data:
500 g is the mass of the solution we want
10% m/m is a sort of concentration, in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution
Therefore we can solve this, by a rule of three:
In 100 g of solution we have 10 g of K₂CO₃
In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃
<u><em>Answer:</em></u>
<u><em>Explanation:</em></u>
Phosphate ion has covalent bond. As we known , covalent bond is formed by sharing of electrons between two atoms. As in this case, P form three single covalent bond with three oxygen atoms and one double covalent bond with one oxygen . The formal charges is -3.
While He is present in mono atomic form
NaI have ionic bond which is formed by donating electrons from one atom and other accept.
Ag is present independently with no other atom.
Answer:
1 mole of iron =6.023×10^23 particles
1 particles of iron=1/6.023×10^23 mole
7.46×10^25 particles =1/6.023×10^23×7.46×10^25
=1.238×10^48 mole is a required answer.
