Answer:
12.5 ft/s
Explanation:
Height of person = 6 ft
height of lamp post = 10 ft
According to the question,
dx / dt = 5 ft/s
Let the rate of tip of the shadow moves away is dy/dt.
According to the diagram
10 / y = 6 / (y - x)
10 y - 10 x = 6 y
y = 2.5 x
Differentiate both sides with respect to t.
dy / dt = 2.5 dx / dt
dy / dt = 2.5 (5) = 12.5 ft /s
Answer:
the answers should be B and D
Answer:
2. +0.2 C
Explanation:
When the two spheres touch, the total charge will be redistributed such that the two spheres are at same potential:
The potential can be rewritten as ratio between the charge on the sphere (Q) and the capacitance of the sphere (C):
Since the two spheres are identical, they have same capacitance:
So we can write
And since the total charge is
And this charge will be redistributed equally on the two spheres (
), we have
The amount of power required to move the 120 Kg person to a distance of 35 m in 150 s is 274.4 W
<h3>How to determin the power</h3>
Power is simply defined as the rate at which work is done. It can be expressed mathematically as
Power (P) = work (W) / time (t)
But
Work = force (F) × distance (d)
Therefore,
P = Fd / t
With the above formula, we can obtain the power as follow:
- Mass (m) = 120 Kg
- Distance (d) = 35 m
- Time (t) = 150 s
- Acceleration due to gravity (g) = 9.8 m/s²
- Force (F) = mg = 120 × 9.8 = 1176 N
- Power (P) = ?
P = Fd / t
P = (1176 × 35) / 150
P = 41160 / 150
P = 274.4 W
Thus, the power is 274.4 W
Learn more about power:
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Answer:
In parallel circuits, if one element has a problem, it can be eliminated and the rest of the elements continue to work.
Explanation:
There are two ways to connect electrical circuits, in series and in parallel.
Series circuits have the problem that when one element is damaged, the entire circuit is interrupted and runs out of power.
In parallel circuits, if one element has a problem, it can be eliminated and the rest of the elements continue to work.
In Breaker it is connected in series so that when some maintenance is needed, all the energy can be interrupted simultaneously and if some equipment tries to consume a lot of energy, the circuit prevents this action by interrupting the energy of the entire circuit
