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I am Lyosha [343]
3 years ago
5

What is a frequency of a ships whistle if the velocity of sound is 340 meters/ second and the wave length is 1.70?

Physics
1 answer:
lyudmila [28]3 years ago
3 0

Answer:

A

Explanation:

As u will divide the sound of air with The length which is also the alternative formula for calculating frequency

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A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 5.12 g coins stacked over the 24.2 cm mark, th
pashok25 [27]

Answer:

The mass of the meter stick is  1.66054054054g

Explanation:

Here since the meter stick is in equilibrium position its net torque and net force should be equal to zero

      Since at the begging the meter stick is balanced at center of the meter stick that means its center of mass should be present at 50.0cm

Now lets consider the later case where stick is balanced by two 5.12 g coins .

Here torque due to two coins = t_{c} = 5.12\times(27.8-24.2)\times2\times9.8

  Torque due to weight of meter stick =  t_{m} =  m\times(50-27.8)\times9.8

  where m = mass of the meter stick

    Here t_{c} = t_{m}.

Upon equating we will be getting mass of the meter stick =1.66054054054g

4 0
3 years ago
A bullet is shot horizontally from shoulder height (1.5 m) with an initial speed 200 m/s. (a) How much time elapses before the b
guapka [62]
<h2>Answer: (a)t=0.553s, (b)x=110.656m</h2>

Explanation:

This situation is a good example of the projectile motion or parabolic motion, in which the travel of the bullet has two components: x-component and y-component. Being their main equations as follows:

x-component:

x=V_{o}cos\theta t   (1)

Where:

V_{o}=200m/s is the bullet's initial speed

\theta=0 because we are told the bullet is shot horizontally

t is the time since the bullet is shot until it hits the ground

y-component:

y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}   (2)

Where:

y_{o}=1.5m  is the initial height of the bullet

y=0  is the final height of the bullet (when it finally hits the ground)

g=9.8m/s^{2}  is the acceleration due gravity

<h2>Part (a):</h2>

Now, for the first part of this problem, the time the bullet elapsed traveling, we will use equation (2) with the conditions given above:

0=1.5m+200m/s.sin(0) t-\frac{9.8m/s^{2}.t^{2}}{2}   (3)

0=1.5m-\frac{9.8m/s^{2}.t^{2}}{2}   (4)

Finding t:

t=\sqrt{\frac{1.5m(2)}{9.8m/s^{2}}}   (5)

Then we have the time elapsed before the bullet hits the ground:

t=0.553s   (6)

<h2>Part (b):</h2>

For the second part of this problem, we are asked to find how far does the bullet traveled horizontally. This means we have to use the equation (1) related to the x-component:

x=V_{o}cos\theta t   (1)

Substituting the knonw values and the value of t found in (6):

x=200m/s.cos(0)(0.553s)   (7)

x=200m/s(0.553s)   (8)

Finally:

x=110.656m  

4 0
3 years ago
What does a plant use in photosynthesis and what are the products? <br><br> PLEASE HELP:)
LenaWriter [7]

During photosynthesis: Light energy is absorbed by chlorophyll, a green substance found in chloroplasts in some plant cells and algae. Absorbed light energy is used to convert carbon dioxide (from the air) and water (from the soil) into a sugar called glucose. Oxygen is released as a by-product.


7 0
3 years ago
An atom of tungsten (W) has 74 protons. The atomic mass of tungsten is 183.84.
ASHA 777 [7]

Answer:

110

Explanation:

to find neutrons we have to subtract the atomic number from the atomic mass.

atomic mass = 183.84

atomic no = 74

183.84 - 74 = 109.84

round off = 110

3 0
4 years ago
In deep space, there is very little friction. Once they launch a probe into deep space, where there are no external forces actin
zimovet [89]
<span>the scientists want the probe to stop immediately and move at constant velocity.
HAPPY VALENTINES </span>
8 0
4 years ago
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