Question

What is the water pressure at the deepest part of the ocean in the Challenger Deep in the Mariana Trench at 10,994 m below the surface.

Answer 1

Answer:

The pressure is 107417976.4 N$m^{-2}$

Explanation:

The pressure of water at a given height/ depth can be determined by:

Pressure = σhg

Where: σ is the density of water, h is the height/ depth, and g is the gravitational force.

Given that; h = 10994 m, but σ = 997 kg/$m^{3}$ and g = 9.8 m/$s^{2}$

Thus, the pressure of water at the deepest part of the ocean will be:

Pressure = 997 x 10994 x 9.8

               = 997 x 107741.2

               = 107417976.4

Pressure  = 107 420 KN$m^{-2}$

The pressure of water at 10994 m below the surface is 107417976.4 N$m^{-2}$