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Anna007 [38]
3 years ago
11

Is H3O+ polar or non polar? (explain please.)?

Chemistry
1 answer:
pishuonlain [190]3 years ago
8 0
The overall molecule is Polar because the shape of the molecule is Trigonal Pyramidal, which means it has the lone pair electrons. Becuase of the lone pair the pulling is unequal.   

H3O+ has 3 polar bonds. 
To know if the bonds are polar or nonpolar find the difference of the element's electronegativity charge. 
H has electronegativity charge of 2.2, and O has 3.4.
Always subtract the smaller number from the greater one. 
So 3.4 - 2.2 = 1.2 
If the difference is from 0-0.4 the bond is nonpolar, but if it's from 0.5-1.9 the bond is polar. 
So, 1.2 is polar bond. So H3O+ has 3 polar bonds, and the overall molecule is polar too. 

A simple way to know if it's polar or nonpolar is to draw the lewis dot structure, and use VSEPR. 

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Balance the equations below by adding coefficients. Enter a number in each blank, entering "1" when necessary.
neonofarm [45]

Answer:

1. CO₂ → C + O₂

2. Fe₂ + O₂ → 2FeO

3. 2Al + 3CuO→  Al₂O₃  +  3Cu

Explanation:

1. 1 mol of CO₂ decomposes to 1 mol of C and 1 mol of oxygem

2. 1 mol of Fe₂ reacts with 1 mol of oxygen to produce 2 moles of iron (II) oxide

3. 2 moles of Al, reacts with 3 moles of cupper(II) oxide to produce 1 mol of aluminum dioxide and 3 moles of cupper

3 0
3 years ago
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If an unknown sample contains 39.04% sulfuric acid by mass, then a 0.9368 g of that sample would require _____ mL of 0.2389 M Na
bonufazy [111]

Answer:

A) 31.22

Explanation:

The reaction of sulfuric acid with NaOH is:

H₂SO₄ + 2 NaOH → Na₂SO₄ + 2H₂O

To solve this problem we need to determine the moles of acid that will react, and, using the chemical equation we can determine the moles of NaOH and the volume that a 0.2389M NaOH solution would require to neutralize it.

<em>Moles H₂SO₄ (Molar mass: 98.08g/mol):</em>

0.9368g * 39.04% = 0.3657g H₂SO₄ * (1mol / 98.08g) =

3.7289x10⁻³moles H₂SO₄

And moles of NaOH that you require to neutralize the acid are:

3.7289x10⁻³moles H₂SO₄ * (2 moles NaOH / 1 mole H₂SO₄) =

7.4578x10⁻³ moles NaOH

Using a 0.2389M NaOH solution:

7.4578x10⁻³ moles NaOH * (1L / 0.2389mol) = 0.03122L = 31.22mL

Right answer is:

<h3>A) 31.22 </h3>

5 0
3 years ago
One atomic model describes electrons moving in clouds around the nucleus.
bixtya [17]

Answer: D.  It is the currently accepted atomic model.

Explanation:

It is the mordern atomic model, also known as the Electron Cloud Model. Indicating that the nucleus of an atom is surrounded by a cloud of electrons.

8 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST
snow_tiger [21]

Answer:

I think it's B

Explanation:

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5 0
2 years ago
"acid is responsible for the odor in rancid butter. a solution of 0.25 m butyric acid has a ph of 2.71. what is the ka for"
Salsk061 [2.6K]

Answer:- The Ka for the acid is 1.53*10^-^5 .

Solution:- In general, monoprotic acid could be represented by HA. The dissociation equation for the ionization of HA is written as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

Now, we make the ice table for this equation as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

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C -X +X +X

E (0.25 - X) X X

where, I stands for initial concentration, C stands for change in concentration and E stands for equilibrium concentration.

X is the change in concentration and from ice table it's same as the concentration of hydrogen ion that is calculated from given pH.

Ka = [H^+][A^-]\frac{1}{HA}

Where, Ka is the acid ionization constant. Let's plug in the values.

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Let's calculate the value of X first using the equation:

pH = -log[H^+][/tex]

on taking antilog ob above equation we get:

[H^+]=10^-^p^H

[H^+]=10^-^2^.^7^1

[H^+] = 0.00195

So, X = 0.001195

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Ka=\frac{(0.00195)^2}{0.25-0.00195}

Ka=1.53*10^-^5

So, the value of Ka for butyric acid is 1.53*10^-^5 .

8 0
3 years ago
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