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joja [24]
3 years ago
12

PLEASE HELP! ONLY SERIOUS ANSWERS! I APPRECIATE ANYTHING!! 30PTS!!!

Chemistry
1 answer:
xenn [34]3 years ago
5 0
1 is b 2 is a 3 is d 4 is a 5 is c
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When the atoms of two substances joined to make a new substance the process is called?
s344n2d4d5 [400]
The answer to your question is: Chemical Reaction. 
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3 years ago
What does the nucleus of a atom contain?
givi [52]
It contains neutrons, which have no charge. Protons which have a positive charge and electrons which have a negative charge. These are all called subatomic particles
3 0
3 years ago
A gallon of paint covers 350 square feet.
trapecia [35]

Answer:

2,137... gallons

Explanation:

(160+140+14x16x2)/350=2,137...

4 0
2 years ago
10 m3 of carbon dioxide is originally at a temperature of 50 °C and pressure of 10 kPa. Determine the new density and volume of
Dimas [21]

Answer : The new density and new volume of carbon dioxide gas is 0.2281 g/L and 7.2m^3 respectively.

Explanation :

First we have to calculate the new or final volume of carbon dioxide gas.

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 10 kPa

P_2 = final pressure of gas = 15 kPa

V_1 = initial volume of gas = 10m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 50^oC=273+50=323K

T_2 = final temperature of gas = 75^oC=273+75=348K

Now put all the given values in the above equation, we get:

\frac{10kPa\times 10m^3}{323K}=\frac{15kPa\times V_2}{348K}

V_2=7.2m^3

The new volume of carbon dioxide gas is 7.2m^3

Now we have to calculate the new density of carbon dioxide gas.

PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}

Formula for new density will be:

\rho_2=\frac{P_2M}{RT_2}

where,

P_2 = new pressure of gas = 15 kPa

T_2 = new temperature of gas = 75^oC=273+75=348K

M = molar mass of carbon dioxide gas = 44 g/mole

R = gas constant = 8.314 L.kPa/mol.K

\rho = new density

Now put all the given values in the above equation, we get:

\rho_2=\frac{(15kPa)\times (44g/mole)}{(8.314L.kPa/mol.K)\times (348K)}

\rho_2=0.2281g/L

The new density of carbon dioxide gas is 0.2281 g/L

5 0
3 years ago
Write a balanced equation for the complete combustion of 2,3-dimethylbutane. use the molecular formula for the alkane (c before
Nuetrik [128]

2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

<em>Step 1</em>. Write the <em>condensed structural  formula</em> for 2,3-dimethylbutane.

(CH_3)_2CHCH(CH_3)_2

<em>Step 2</em>. Write the <em>molecular formula</em>.

C_6H_14

<em>Step 3</em>. Write the <em>unbalanced chemical equation</em>.

C_6H_14 + O_2 → CO_2 + H_2O

<em>Step 4</em>. Pick the <em>most complicated-looking formula</em> (C_6H_14) and balance its atoms (C and H).

<em>1</em>C_6H_14 + O_2 → <em>6</em>CO_2 + <em>7</em>H_2O

<em>Step 5</em>. Balance the <em>remaining atoms</em> (O).

1C_6H_14 + (<em>19/2</em>)O_2 → 6CO_2 + 7H_2O

Oops! <em>Fractional coefficients</em>!

<em>Step 6</em>. <em>Multiply all coefficients by a number</em> (2) to give integer coeficients..

2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

4 0
3 years ago
Read 2 more answers
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