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When the atoms of two substances joined to make a new substance the process is called?

s344n2d4d5 [400]

The answer to your question is: Chemical Reaction.

6 0

3 years ago

What does the nucleus of a atom contain?

givi [52]

It contains neutrons, which have no charge. Protons which have a positive charge and electrons which have a negative charge. These are all called subatomic particles

3 0

3 years ago

A gallon of paint covers 350 square feet.

trapecia [35]

Answer:

2,137... gallons

Explanation:

(160+140+14x16x2)/350=2,137...

4 0

2 years ago

10 m3 of carbon dioxide is originally at a temperature of 50 °C and pressure of 10 kPa. Determine the new density and volume of

Dimas [21]

Answer : The new density and new volume of carbon dioxide gas is 0.2281 g/L and $7.2m^3$ respectively.

Explanation :

First we have to calculate the new or final volume of carbon dioxide gas.

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 10 kPa

$P_2$ = final pressure of gas = 15 kPa

$V_1$ = initial volume of gas = $10m^3$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $50^oC=273+50=323K$

$T_2$ = final temperature of gas = $75^oC=273+75=348K$

Now put all the given values in the above equation, we get:

$\frac{10kPa\times 10m^3}{323K}=\frac{15kPa\times V_2}{348K}$

$V_2=7.2m^3$

The new volume of carbon dioxide gas is $7.2m^3$

Now we have to calculate the new density of carbon dioxide gas.

$PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}$

Formula for new density will be:

$\rho_2=\frac{P_2M}{RT_2}$

where,

$P_2$ = new pressure of gas = 15 kPa

$T_2$ = new temperature of gas = $75^oC=273+75=348K$

M = molar mass of carbon dioxide gas = 44 g/mole

R = gas constant = 8.314 L.kPa/mol.K

$\rho$ = new density

Now put all the given values in the above equation, we get:

$\rho_2=\frac{(15kPa)\times (44g/mole)}{(8.314L.kPa/mol.K)\times (348K)}$

$\rho_2=0.2281g/L$

The new density of carbon dioxide gas is 0.2281 g/L

5 0

3 years ago

Write a balanced equation for the complete combustion of 2,3-dimethylbutane. use the molecular formula for the alkane (c before

Nuetrik [128]

2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

Step 1. Write the condensed structural formula for 2,3-dimethylbutane.

(CH_3)_2CHCH(CH_3)_2

Step 2. Write the molecular formula.

C_6H_14

Step 3. Write the unbalanced chemical equation.

C_6H_14 + O_2 → CO_2 + H_2O

Step 4. Pick the most complicated-looking formula (C_6H_14) and balance its atoms (C and H).

1C_6H_14 + O_2 → 6CO_2 + 7H_2O

Step 5. Balance the remaining atoms (O).

1C_6H_14 + (19/2)O_2 → 6CO_2 + 7H_2O

Oops! Fractional coefficients!

Step 6. Multiply all coefficients by a number (2) to give integer coeficients..

2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

4 0

3 years ago

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