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DiKsa [7]
1 year ago
14

What mass will accelerate at 3 m/s² when a net force of 150 N acts on it?

Physics
1 answer:
vodomira [7]1 year ago
7 0

Answer:

\huge\boxed{\sf m = 50\ kg}

Explanation:

<h3><u>Given data:</u></h3>

Acceleration = a = 3 m/s²

Force = F = 150 N

<h3><u>Required:</u></h3>

Mass = m = ?

<h3><u>Formula:</u></h3>

F = ma

<h3><u>Solution:</u></h3>

Put the givens in the formula

150 = m (3)

Divide 3 to both sides

150/3 = m

50 kg = m

m = 50 kg

\rule[225]{225}{2}

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A student fills a tank of radius r with water to a height of h1 and pokes a small, 1.0 cm diameter hole at a distance h2 from th
Alik [6]

when a hole is made at the bottom of the container then water will flow out of it

The speed of ejected water can be calculated by help of Bernuolli's equation and Equation of continuity.

By Bernoulli's equation we can write

Po + \frac{1}{2}\rho v_1^2 + \rho g h = Po + \frac{1}{2}\rho v_2^2 + \rho g *0

Now by equation of continuity

A_1v_1 = A_2v_2

\pi (0.2)^2 v_1 = \pi (0.01)^2 v_2

from above equation we can say that speed at the top layer is almost negligible.

v_1 = 0

now again by equation of continuity

\rho g h = \frac{1}{2} \rho v^2

v = \sqrt{2 g h}

here we have

h = h_1 - h_2

h = 0.50 - 0.03 = 0.47m

now speed is given by

v = \sqrt{2* 9.8 * 0.47}

v = 3.03 m/s

7 0
3 years ago
Convert 4 radians to degrees A. 242.6° B. 9.6° C. 229.2° D. 6.8°
muminat
The central angle of a circle is 360° or 2π radians.

Therefore
1 radian = (360 degrees)/(2π radians) = 180/π degrees/radian.
4 radians = (4 radians)*(180/π degrees/radian) = 229.18 degrees.

Answer: C.  229.2°
8 0
3 years ago
Read 2 more answers
If the person drops box from 3.8 m how much energy is transferred from potential energy to kinetic energy
kotykmax [81]

Answer:

Kinetic energy

When work is done the energy is transferred from one type to another. This transferred energy may appear as kinetic energy.

For example, when you pedal your bicycle so that its speed increases, you are doing work to transfer chemical energy from your muscles to the kinetic energy of the bicycle.

Kinetic energy is the energy an object possesses by virtue of its movement. The amount of kinetic energy possessed by a moving object depends on the mass of the object and its speed. The greater the mass and the speed of the object the greater its kinetic energy.

The kinetic energy Ek of an object of mass m at a speed v is given by the relationship

{E_k} = \frac{1}{2}m{v^2}

m is the mass of the object in kilograms ( kg) and v is the speed of the object in metres per second ( m\,s^{-1}).

Explanation:

When work is done on an object it may also lead to energy being transferred to the object in the form of gravitational potential energy of the object.

Gravitational potential energy is the energy an object has by virtue of its position above the surface of the Earth. When an object is lifted, work is done. When work is done in raising the height of an object, energy is transferred as a gain in the gravitational potential energy of the object.

For example, suppose you lift a suitcase of mass m through a height h. The weight W of the suit case is a downward force of size mg. In lifting the suitcase, you would have to pull upwards on it with a force equal in size to its weight, mg.

Two suitcases. One has a green force arrow pointing up labelled F and a purple force arrow pointing down labelled 'Weight = mg'. The other case is raised by a height labelled h.

Suitcases with forces and height labelled

When this force (equal to the weight mg, but upwards) is applied to the suitcase over the distance h:

Work\,done=force\,\times\,distance\,upwards=mg\,\times\,h

This energy is transferred to potential energy when raising the object through a known height.

Energy = mass \times gravitational\,field\,strength \times height

E = m \times g \times h

This is the relationship used to calculate gravitational potential energy.

{E_p} = mgh

where m is the mass of the object in kilograms (kg), g is the gravitational field strength, (for positions near the surface of the Earth g = 9∙8 newtons per kilogram ( N kg ^{-1} and h is the height above the surface of the Earth in metres ( m).

8 0
3 years ago
An airplane cabin is pressurized to 570 mmhg. what is the pressure inside the cabin in atmospheres?
abruzzese [7]
1 atm corresponds to 760 mmHg, so we can set up a simple proportion to find how many atmospheres correspond to 570 mmHg:
1 atm: 760 mmHg = x: 570 mmHg
and from this, we find
x= \frac{1 atm \cdot 570 mmHg}{760 mmHg} =0.75 atm
8 0
3 years ago
Read 2 more answers
In a lab, four balls have the same velocities but different masses.
olya-2409 [2.1K]

Answer:

New Momentum of Ball B=13.2 \frac{\mathrm{kgm}}{\mathrm{s}}

<u>Explanation:</u>

Given:

Mass of Ball A=1kg

Mass of Ball B= 2kg

Mass of Ball C=5kg

Mass of Ball D=7kg

Velocities of A=B=C=D=2.2\frac{m}{s}

Momentum of Ball A=2.2\frac{k g m}{s}

Momentum of Ball B=4.4 \frac{k g m}{s}

Momentum of Ball C=11\frac{k g m}{s}

Momentum of Ball D=15\frac{k g m}{s}

To Find:

Change in Momentum When of Ball B gets tripled

Solution:

Though all balls have same velocity, thus we get

Velocities of A=B=C=D=2.2\frac{m}{s}

Initial Momentum of Ball B=4.4\frac{k g m}{s}

If the Mass of Ball B gets tripled;

We get New Mass of Ball B=3×Actual Mass of the ball

                                            =3×2=6kg

Thus we get Mass of Ball B=6kg

According to the formula,  

Change in momentum of Ball B \Delta p=m \times \Delta v

Where \Delta p=change in momentum

          m=mass of the ball B

         \Delta v=change in velocity ball B

And \Delta v=v, since all balls, have same velocity

Thus the above equation, changes to

         \Delta p=m \times v

Substitute all the values in the above equation we get

         \Delta p=6 \times 2.2

                     =13.2 \frac{\mathrm{kgm}}{\mathrm{s}}  

Result:

 Thus the New Momentum of ball B=13.2 \frac{\mathrm{kgm}}{\mathrm{s}}

3 0
3 years ago
Read 2 more answers
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