Answer:
24.525 g of sulfuric acid.
Explanation:
Hello,
Normality (units of eq/L) is defined as:
Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:
Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:
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A binary ionic compound is composed of ions of two different elements. One of which is a metal, and the other a non-metal
Its all of the above.
- I took the test and mine is correct.
Answer : The mass of calcium chloride (in g) needed is, 1.92 grams.
Explanation : Given,
Boiling point of elevation constant 
for water = 
Mass of water (solvent) = 
Molar mass of 
= 110.98 g/mole
Formula used :
where,
= change in boiling point = 
i = Van't Hoff factor = 3 (for electrolyte)
= boiling point constant for water
m = molality
Now put all the given values in this formula, we get
Therefore, the mass of calcium chloride (in g) needed is, 1.92 grams.
