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Firlakuza [10]
3 years ago
7

Transferring charge by touching or rubbing is called-

Chemistry
1 answer:
mina [271]3 years ago
3 0

Answer:

A) Charging by contact

Explanation:

Transfer of heat by direct contact, Heat energy is conducted from the hotter medium to the cooler medium

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You are given a bottle of NaOH of an unknown concentration. You are tasked with determining the concentration of this solution.
Salsk061 [2.6K]

Answer:

0.07975 M NaOH

Explanation:

First determine the molarity of your acid, KHP. Convert grams to moles using the MW given and then divide by the volume of water.

0.3175 g KHP • (1 mol KHP / 204.2 g KHP) = 0.001555 mol KHP

0.001555 mol KHP / 0.040 L = 0.03888 M KHP

The reaction between KHP and NaOH is one-to-one, so you can just use M1V1 = M2V2 to solve for M2 (the molarity of NaOH).

M1 = 0.03888 M KHP

V1 = 40 mL

M2 = ? M NaOH

V2 = 19.45 mL NaOH

(0.03888 M KHP)(40 mL) = M2(19.5 mL NaOH)

M2 = 0.07975 M NaOH

4 0
3 years ago
help asap show work | a gas with a volume of 13L at a pressure of 197 kPA is allowed to expand to a volume of 23L. what is the p
Lera25 [3.4K]

Answer:

<h2>111 kPa</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

We have

P_2 =  \frac{13 \times 197000}{23}  =  \frac{2561000}{23}  \\  = 111347.826...

We have the final answer as

<h3>111 kPa </h3>

Hope this helps you

5 0
3 years ago
How many moles are in 264 g of gold, Au?<br>1 point<br>​
Brut [27]

Answer: 1/2

Explanation:

5 0
3 years ago
Read 2 more answers
A 5.0 l sample of gas is cooled from 298 k to 278 k at constant pressure. what is the new volume of the gas?
olga nikolaevna [1]
In order to calculate the final volume of the gas, we may apply Charles Law, which states that for a fixed amount of gas subject to a fixed amount of pressure, the volume and temperature of a gas are directly proportional. This is:
V/T = constant
Using this equation,
5/298 = V/278
V = 4.66 L

The final volume of the gas is 4.66 liters
5 0
4 years ago
An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu
chubhunter [2.5K]

Answer:

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

The density of a proton is 6.278\times 10^{14} g/cm^3.

Explanation:

Diameter of the atom ,d = 2.50 Å

Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\pi r^3..[1]

Diameter of the nucleus ,d' = 9.00\times 10^{-5}\AA

Radius of the nucleus ,r' = 0.5 d'=0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA

Volume of nucleus = V'

V=\frac{4}{3}\pi r'^3..[2]

Dividing [2] by [1]

\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}

=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}

\frac{V'}{V}=4.6656\times 10^{-14}

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

Diameter of the proton ,d = 1.72\times 10^{-15} m = 1.72\times 10^{-13} cm

1 m = 100 cm

Radius of the proton,r = 0.5 d=0.5\times 1.72\times 10^{-13} cm=8.6\times 10^{-14} cm

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3

Mass of proton, m = 1.0073 amu = 1.0073\times 1.66054\times 10^{-24} g

1 amu = 1.66054\times 10^{-24} g

Density of the proton : d

d=\frac{m}{V}=\frac{1.0073\times 1.66054\times 10^{-24} g}{2.664\times 10^{-39}cm^3}=6.278\times 10^{14} g/cm^3

The density of a proton is 6.278\times 10^{14} g/cm^3.

5 0
4 years ago
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