Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol
Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol
Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
= (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
= 176.15 kJ - 84.78 kJ = 91.38 kJ
Answer:The outer core of the Earth contains a lot of iron in a molten state. As the Earth spins this molten iron moves and creates the Earth's magnetic field. The Earth behaves as if there is a huge bar magnet at its centre. The shape of the field around the Earth is very similar to the field around a bar magnet
Explanation:
Answer:
Can you please post a pictah.
Explanation:
The correct answer is H2SO3 I took the assignment already
Answer with Explanation:
This is expirament based Q
1) Bring a magnet near ... the Cobalt will come out of te mixture and get attracted to magnet
2) Disolve it in a solution of ethanol. The Idoine gets dissolve and the other doesnt.
Hope im right!!
