Someone help this is so hard
2 answers:
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Explanation:
As it is given that stream A is super heated. From stream tables, we get that specific enthalpy, () is 3054.29 kJ/kg.
For stream B, it is saturated water at 25 degree celsius. It's is 2546.54 kJ/kg.
Stream C, data will be as follows.
P = 200 kPa, = 0.9
So, =
= 504.47 + 0.9 \times 2201.7
= 2486 kJ/kg
Now, energy balance formula will be as follows.
=
=
= 28.16 kg/s
Hence, inflow of saturated liquid is 28.16 kg/s. According to steam table, temperature of wet steam is
Mass flow rate of out flow is 31.16 kg/s.