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steposvetlana [31]
2 years ago
14

guys please help me i've been struggling with this question all school day (what reaction is ___ Mg + ____ H₂SO₄ --> ____ H₂

+ ____ MgSO₄ )
Chemistry
1 answer:
love history [14]2 years ago
5 0

Answer:

Single replacement reaction

Explanation:

It's already balanced so it would just be Mg + H2SO4 --> H2 + MgSO4

The formula for a single replacement reaction is

A + BC --> B + AC

A=Mg

B=H2

C=SO4

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Imagine that you helped to discover a new element; A=302;Z=119. How many protons, electrons, and neutrons are in each atom it th
oee [108]

Explanation:

Given that,

Mass number, A = 302

Atomic number, Z = 119

We know that, atomic number = no of protons

Protons = 119

Mass no. = No. of neutrons + No. of protons

302 = No. of neutrons + 119

No. of neutrons = 302 - 119

= 183

No. of electrons = No. of protons

= 119

5 0
3 years ago
In terms of their electron configurations, why is cesium more likely to lose its valence electron than potassium?
Harlamova29_29 [7]

Explanation:

use the term electron sheilding, the more electrons between the valence el3ctron and nucleus the easier to lose the valence electron (more sheilding = easier to lose)

5 0
3 years ago
HELP ASAP will give BRAINLIEST!
katovenus [111]

Answer:

Newton's 1st law,

Explanation:

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3 years ago
Plants such as _______________ provided much nitrogen to the soil.
Allushta [10]

Answer:

Abiotic

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Its because it includes water, sunlight, tempature and soil

6 0
2 years ago
Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . Calculate t
Sedbober [7]

Answer:

Approximately 6.30\times 10^{-3}\;\rm mol.

Explanation:

The gallium here is likely to be produced from a \rm NaGaO_2\, (aq) solution using electrolysis. However, the problem did not provide a chemical equation for that process. How many electrons will it take to produce one mole of gallium?

Note the Roman Numeral "\mathtt{(III)}" next to \rm Ga.  This numeral indicates that the oxidation state of the gallium in this solution is equal to +3. In other words, each gallium atom is three electrons short from being neutral. It would take three electrons to reduce one of these atoms to its neutral, metallic state in the form of \rm Ga\, (s).

As a result, it would take three moles of electrons to deposit one mole of gallium atoms from this gallium \mathtt{(III)} solution.

How many electrons are supplied? Start by finding the charge on all the electrons in the unit coulomb. Make sure all values are in their standard units.

t = \rm 80.0\; min = 80.0\; min \times 60\;s \cdot min^{-1} = 4800\; s.

Q = I \cdot t = \rm 0.380 \; A \times 4800 \; s = 1.824\times 10^3\; C.

Calculate the number of electrons in moles using the Faraday's constant. This constant gives the size of the charge (in coulombs) on each mole of electrons.

\begin{aligned} n(\text{electrons}) &= \frac{Q}{F} \cr &= \rm \dfrac{1.824\times 10^3\; C}{96485.332\; C \cdot mol^{-1}}\cr &\approx \rm 1.89\times 10^{-2}\; mol \end{aligned}.

It takes three moles of electrons to deposit one mole of gallium atoms \rm Ga\, (s). As a result, \rm 1.89\times 10^{-2}\; mol of electrons would deposit \displaystyle \rm \frac{1}{3}\times 1.89\times 10^{-2}\; mol \approx 6.30\times 10^{-3}\; mol of gallium atoms \rm Ga\, (s).

8 0
3 years ago
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