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Iteru [2.4K]
3 years ago
14

Help ! i don’t know how to calculate this , it’s due at 11:59 pm

Chemistry
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

1 x 2 x 3 x 4 x 5 etc. sorry if wrong i have never learned this...

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Which type of formula represents the simplest whole-number ratio of atoms of the elements in a compound?
sleet_krkn [62]
The empirical formula represents the simplest whole number shows the simplest whole number ratio of atoms in a compound.  An example of this is the empirical formula for glucose (C₆H₁₂O₆) is C₃H₆O₃.  

I hope this helps.  Let me know if anything is unclear.
5 0
3 years ago
(Giving Brainiest)<br><br> I nep help with this assessment!
kotykmax [81]

Answer:Could you give a more detailed explanation like what exactly do you need/want?

Explanation:

5 0
3 years ago
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HELP!!!!!!!!!!!! ASAP!!!!!!!!!!!!!!!!!!! CHEMISTRY TEST!!!!!!!!!!!!!! 53 POINTS
lbvjy [14]

Answer:

9.1 KJ

Explanation:

First we must find the number of moles of HBr involved;

number of moles of HBr= mass of HBr/ molar mass of HBr

But molar mass of HBr= 80.91 g/mol

Given mass of HBr from the question= 20.1g

Hence;

Number of moles of HBr= 20.1 g/80.91g

Number of moles of HBr= 0.25 moles of HBr

If 2 moles of HBr has a heat of formation of 72.80KJ

Then 0.25 moles of HBr will have a heat of formation of 0.25× 72.80/2= 9.1 KJ

Therefore; 20.1 g of HBr will have a heat of formation of 9.1 KJ

3 0
3 years ago
11. A 4.175 gram sample of a certain hydrate of copper (II) sulfate, CuSO,• xH,O, is heated until all
Wewaii [24]

The  formula of the hydrate = CuSO₄• 3H₂O

<h3>Further explanation</h3>

Given

4.175 grams sample CuSO₄• xH₂O

3.120 grams anhydrous compound CuSO₄

Required

The formula

Solution

mass of H₂O driven off :

= 4.175 - 3.12

= 1.055 g

MW CuSO₄ = 159.5 g/mol

MW H₂O = 18 g/mol

mol ratio of CuSO₄ : H₂O :

= 3.12/159.5 : 1.055/18

= 0.01956 : 0.05861

= 1 : 3

3 0
4 years ago
Can someone help me answer this
Ostrovityanka [42]

Answer:sorry

Explanation:

3 0
3 years ago
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