The average kinetic energy of translation of oxygen molecules in the gas is 5.05 × 10⁻²¹
The given data is
n = 2
v = 20
P = 92
K.E = 3 / 2 KbT
= 3 / 2 PV / N
= 3 / 2 Pv / nNa
K.E = 3 / 2 × 9 × 1.013 × 10⁵ × 20 × 10⁻³ / 2 × 6.022 × 10²³
K. E = 5.05 × 10⁻²¹ J
<h3>Average kinetic energy</h3>
The average kinetic energy (K) is equal to one half of the mass of each gas molecule times the RMS speed squared
Hence, the average kinetic energy is 5.05 × 10⁻²¹ J
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In the ground state, only one. But for bonding, all three valence electrons are used, and the atom acquires a slightly excited state.
Answer:
True
Hydrogen bond is a partial intermolecular bonding interaction between a lone pair on an electron rich donor atom, particularly the second-row elements nitrogen (N), oxygen (O), or fluorine (F), and the antibonding orbital of a bond between hydrogen (H) and a more
electronegative atom or group. Such an interacting system is generally denoted Dn–H···Ac, where the solid line denotes a polar covalent bond, and the dotted or dashed line indicates the hydrogen bond. The use of three centered dots for the hydrogen bond is specifically recommended by the IUPAC. While hydrogen bonding has both covalence and electrostatic contributions, and the degrees to which they contribute are currently debated, the present evidence strongly implies that the primary contribution is covelant.
Hydrogen bonds can be intermolecular (occurring between separate molecules) or
intramolecular (occurring among parts of the same molecule)
