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juin [17]
3 years ago
12

This unit discusses in detail the role of catalysts to lower the activation energy of reactions. The term catalyst appears in no

nscientific discussions to refer to something that provokes or speeds significant change or action. Consider this example from the 2006 Associated Press article "Chernobyl cover-up a catalyst for glasnost":
"For the Soviet Union, Chernobyl was a catalyst that forced the government into an unprecedented show of openness that paved the way for reforms leading to the Soviet collapse"

Discuss how this scientific term has made its way into common usage. Does the term catalyst carry the same meaning in regular usage? How is it used differently in a scientific context compared to a nonscientific contexte​
Chemistry
1 answer:
Margaret [11]3 years ago
8 0
I have the link i found the answers for this just start with the first work to there search it up.


Explain
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Balance the following equation. Then determine the mole ratio of Ca(OH)2:Al(OH)3. Al2(SO4)3 + Ca(OH)2 Al(OH)3 + CaSO4
anygoal [31]
To balance the reaction, we look at the number of atoms of each element we have. It should be equal for both sides. The balanced reaction is:
<span>
Al2(SO4)3 + 3Ca(OH)2 =  2Al(OH)3 + 3CaSO4

The ratio of calcium hydroxide and aluminum hydroxide is 3:2.</span>
6 0
4 years ago
An electrochemical cell contains a standard hydrogen electrode and a cathode consisting of a metallic chromium electrode, Cr(s),
stira [4]

Answer:

c. I, II and III

Explanation:

The cell is as follows

Cr / Cr⁺²(1M) // H⁺ ( 1 M ) / H₂

Standard reduction potential of hydrogen cell is zero . Standard reduction potential is negative E for Cr⁺² / Cr(1M) half cell

Cell potential = Ecathode - Eanode

= 0 - ( - E)

= E

E is cell potential and also standard cell potential or emf of the cell .

Standard reduction potential that is for Cr3+/Cr.  is  - E .

Hence statement I , II , III are right . IV th statement is wrong because of sign

Option c is correct.

5 0
3 years ago
Helppppp plz ASAP DON’T GUESS
PolarNik [594]

Explanation:

A B C D isme koyi ans hain doond lo

4 0
3 years ago
Calculate the molar mass of butane. Butane's rate of diffusion is 3.8 times slower than that of hleium.
Pie

Answer:

58 g/mol

Explanation:

According to Graham's law, the rate of diffusion of a gas (r) is inversely proportional to the square root of its molar mass (M). Butane's rate of diffusion is 3.8 times slower than that of helium, that is, rButane = rHe/3.8, or rHe/rButane = 3.8. Then,

\frac{rHe}{rButane} =3.8=\sqrt{\frac{M(Butane)}{M(He)} } =\sqrt{\frac{M(Butane)}{4.00g/mol} } \\M(Butane)=3.8^{2} \times 4.00g/mol\\M(Butane)=58g/mol

8 0
3 years ago
Read 2 more answers
Can someone solve c and d? ​
tangare [24]

Answer:

Na + + e - → Na.

Pb 2+ + 2e - → Pb.

2H + + 2e - → H 2

Explanation:

7 0
3 years ago
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