1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timurjin [86]
2 years ago
11

the mass of an object is 90 kg calculate weight of the same object on the surface of the moon.(acceleration due to gravity on th

e Moon surface is 1/6 of the value of acceleration due to the Gravity on Earth) also calculate the weight of the same object on earth surface.​
Physics
2 answers:
aalyn [17]2 years ago
5 0

Explanation:

the weight of an object is its force exerted by gravity.

on earth we take gravitational acceleration to be 9.8 m/s^2

so the weight of an object on earth is given by F = mg

hence,

F = 90 × 9.8

F = 882 Newtons (weight on earth)

gravitational acceleration on the moon is equal to 9.8/6. so, we can just use the same formula to find the weight on the moon.

F = 90 × 9.8/6

F = 147 Newtons (weight on the moon)

make sure to ask if you need any further guidance.

Maru [420]2 years ago
5 0
W=m*g
W=90*9.8=882N (Earth)
W=90*(9.8/6)=147N (Moon)
Hope this helps
You might be interested in
A grandfather clock keeps time using a pendulum consisting of a light rod connected to a small heavy mass. With a rod of length
german

Answer:

The length of the rod should be

\frac{L}{4} \\

Explanation:

Period of simple pendulum is given by

T=2\pi\sqrt{\frac{l}{g}} \\

We have

\frac{T_1^2}{T_2^2}=\frac{l_1}{l_2}\\\\\frac{2^2}{1^2}=\frac{L}{l_2}\\\\l_2=\frac{L}{4} \\

The length of the rod should be

\frac{L}{4} \\

5 0
3 years ago
if the Horse and Rider have a combined mass of 572 kg what force would be required to accelerate them 5 kph per second
Vlad [161]

Answer:

   Force required to accelerate = 794.44 N

Explanation:

 Force required = Mass of horse x Acceleration of horse

 Mass of horse and rider, m=   572 kg

 Acceleration of horse and rider, a = 5 kph per second

                                      =\frac{5*1000}{60*60} =1.39 m/s^2

  Force required = ma

                             = 572 x 1.39 = 794.44 N

  Force required to accelerate = 794.44 N

8 0
3 years ago
Which describes the average velocity of an ant traveling at a constant speed
yanalaym [24]

Answer: A. The total displacement divided by the time and  C. The slope of the ant's displacement vs. time graph.

Explanation:

Hi! The question seems incomplete, but I found the options on the internt:

A. The total displacement divided by the time.

B. The slope of the ant's acceleration vs. time graph.

C. The slope of the ant's displacement vs. time graph.

D. The average acceleration divided by the time.

Now, since we know the ant is travelling at a constant speed, its average velocity V will be expressed by the following equation:

V=\frac{d}{t}

Where:

d is the ant's total displacement

t is the time it took to the ant to travel to the kitchen

Hence one of the correct options is: A. The total displacement divided by the time

On the other hand, this can be expressed by a displacement vs. time graph graph, where the slope of that line leads to the equation written above. So, the other correct option is: C. The slope of the ant's displacement vs. time graph.

3 0
3 years ago
In a physics laboratory experiment, a coil with 200 turns enclosing an area of 11.8 cm^2 is rotated during the time interval 4.9
Zanzabum

Answer:

Explanation:

Flux through the coil = nBA , n is no of turns , B is magnetic flux and A a is area of the coli

= 200 x 5.6 x 10⁻⁵ x 11.8 x 10⁻⁴

=  13216 x 10⁻⁹ weber .

b ) When the coil becomes parallel to magnetic field  , flux through it will become zero.

c ) e m f induced = change in flux / time

= 13216 x 10⁻⁹ / 4.9 x 10⁻²

= 2697.14 x 10⁻⁷ V

= 269.7 x10⁻⁶

269.7 μV.

6 0
3 years ago
1. A woman driving in a car at 21 m/s pushes down on the gas pedal. 6 seconds later, she is moving at 36 m/s. What was her avera
Furkat [3]

a=Vf-Vi/t=36-21/6=15/6=2.5m/s^2

5 0
3 years ago
Other questions:
  • An old mining tunnel disappears into a hillside. You would like to know how long the tunnel is, but it's too dangerous to go ins
    10·1 answer
  • 0.403 L is equal to: <br> 4.03 mL <br> 40.3 mL <br> 403 mL <br> 4,030 mL
    15·2 answers
  • A box of groceries requires 5.0 Newton’s of force to lift it up 1.0 meter how much work is done
    6·2 answers
  • A point charge of 4.0 µC is placed at a distance of 0.10 m from a hard rubber rod with an electric field of 1.0 × 103 . What is
    7·1 answer
  • What must be true about two objects if heat is flowing between them? the objects must be different temperatures. the objects mus
    15·2 answers
  • At T = 0C and p = 1000mb, 1 g of dry air receives an amount of heat during an isochoric process. It is then observed that its p
    5·1 answer
  • This is an example of A) alpha decay B) beta decay C) gamma decay D) half-life decay
    14·1 answer
  • (6). A car travels in a straight line from city A to city B at a speed of 60kmh-1
    7·1 answer
  • Two charges of magnitude ‒Q and +4Q are located as in the figure below. At which position (A, B,
    15·1 answer
  • Which phenomenon supports the particle model of light?
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!