The amount of heat required is 9.0 kJ.
<em>q = mC</em>Δ<em>T
</em>
Δ<em>T</em> = <em>T</em>_f – <em>T</em>_i = 65 °C – 32 °C = 33 °C
<em>q</em> = 65 g × 4.184 J·°C⁻¹g⁻¹ × 33 °C = 9000 J = 9.0 kJ
Answer:
0.99mol/L
Explanation:
Molarity ( M) = # of moles of solute / volume of solution (L)
Volume of Solution = 100 mL or 0.1 L
Molarity ( M) = # of moles of solute / volume of solution (L)
Molarity (M) = 0.099 mol / 0.1 L = 0.99mol/ L
It is a molecule of the compound.
Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:
Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:
Then, we plug in the variables to obtain:
Regards!
Answer: B) calcium nitrate
