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3 years ago

If you run at an average speed of 10 mi/h, how long will it take

Physics

1 answer:

PSYCHO15rus [73]3 years ago

3 0

Answer:

25 Minutes

Reason:

Because you know mi/h means the miles PER hours, and we know that when we see the word "per" we're dealing with a rate. What we have to do here, is multiply 10(mph) is like the average, or limit. So if I'm running 2.5 miles I multiply 10 x 2.5 to get 25.

Sorce: Brainly.com

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The ozone layer is found in which layer of the atmosphere

prohojiy [21]

This question is incomplete because the options are missing; here is the complete question

The ozone layer is found in which layer of the atmosphere?

A. Stratosphere

B. Mesosphere

C. Thermosphere

D. Troposphere

The correct answer is A. Stratosphere

Explanation:

The ozone layer as indicated by its name is mainly composed of Ozone (O2), this layer is essential for life because it filters ultraviolet radiation and acts as a greenhouse effect gas by trapping part of the heat from the sun. Additionally, the ozone layer is located in the stratosphere, which is the second layer of the atmosphere and can be found between 20 km to 50 km from Earth's surface. Moreover, the existence of the ozone layer in the stratosphere makes the temperature increase with height due to the radiation of the sun filter by ozone.

4 0

3 years ago

An 7.5 × binocular has 3.7-cm-focal-length eyepieces. What is the focal length of the objective lenses? Express your answer to t

elixir [45]

To solve this problem we will apply the concept of magnification, which is given as the relationship between the focal length of the eyepieces and the focal length of the objective. This relationship can be expressed mathematically as,

$\mu = \frac{f_0}{f_e}$

Here,

$\mu$ = Magnification

$f_e$ = Focal length eyepieces

$f_0$ = Focal length of the Objective

Rearranging to find the focal length of the objective

$f_0 = \mu f_e$

Replacing with our values

$f_0 = 7.5* 3.7cm$

$f_0 = 27.75cm$

Therefore the focal length of th eobjective lenses is 27.75cm

5 0

3 years ago

A light beam has speed c in vacuum and speed v in a certain plastic. The index of refraction n of this plastic is

Mnenie [13.5K]

Answer:

$n = \frac{c}{v}$

Explanation:

Refractive Index: It is a measure to find how fast the light travels through a medium. It is ration of the speed of light in vacuum to speed of light in the medium. Speed of light is not constant and varies depending on the density of the medium.

In vacuum the speed of light is 300000 km/s and is denoted by c. When the light beam enters any medium the speed will decrease. Here it is given that the speed in plastic is v. Thus the refractive index(n) is given as:

$n = \frac{c}{v}$

It is a dimensionless no.

3 0

3 years ago

If the force of gravity changes, what happens to the weight of an object?

Nataly [62]

The "weight" is the name we give to the force of gravity on the object. They're the same thing.

7 0

3 years ago

Starting from rest, a crate of mass m is pushed up a frictionless slope of angle theta by a horizontal force of magnitude F. Use

ludmilkaskok [199]

Answer:

v = sqrt[2*(F*h*cot(theta)-mgh)/m]

Explanation:

Work = KE + Ug

F*r=1/2mv^2+mgh

1/2mv^2=F*r-mgh

v=sqrt[2(F*r-mgh)/m]

r=h/tan(theta)=h*cot(theta)

6 0

3 years ago