If you apply a 4 N force to a 2 kg object, how fast will it accelerate? (Your
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Refer to the diagram shown below.
Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.
The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.
The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s
The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°
Answer: 10.2 m/s at 21.5° downstream.
Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.
The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.
The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s
The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°
Answer: 10.2 m/s at 21.5° downstream.
The average rate at which the cable does work is 294,000 J/s.
The given parameters:
- <em>mass, m = 3000 kg</em>
- <em>height, h = 200 m</em>
- <em>time of motion, t = 20 s</em>
The average rate at which the cable does work is calculated as follows;
Thus, the average rate at which the cable does work is 294,000 J/s.
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