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Evgen [1.6K]
3 years ago
5

can someone please please please help me find the spring force constant thank you thank you thank you thank you

Physics
1 answer:
Levart [38]3 years ago
3 0

Answer:

spring force frictonal

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From a hot air balloon that is at rest at a certain height, a projectile is launched horizontally at 30m / s, how fast will it h
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Answer:

A. 50 m/s

Explanation:

Given in the y direction:

v₀ = 0 m/s

a = 10 m/s²

t = 4 s

Find: v

v = at + v₀

v = (10 m/s²) (4 s) + 0 m/s

v = 40 m/s

In the x direction, the velocity is constant at 30 m/s.

The overall speed is:

v² = (30 m/s)² + (40 m/s)²

v = 50 m/s

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3 years ago
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Ben rushin is waiting at a stoplight. when it finally turns green, ben accelerated from rest at a rate of a 6.00 m/s2 for a time
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In the 4.10 seconds that elapsed, Ben reaches a velocity of

v_f=v_0+at\implies v_f=0\,\dfrac{\mathrm m}{\mathrm s}+\left(6.00\,\dfrac{\mathrm m}{\mathrm s^2}\right)(4.10\,\mathrm s)

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In this time, his displacement \Delta x satisfies

{v_f}^2-{v_0}^2=2a\Delta x\implies\left(24.6\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(0\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(6.00\,\dfrac{\mathrm m}{\mathrm s^2}\right)\Delta x

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What is the relationship between electrical power, current, and voltage
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they both uses electric volts

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Describe the objects that make up Saturn's rings. Your answer should include the range of sizes of objects in the rings, and the
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oil is flowing through a tube that has two different cross-sectional areas. at position a where the radius of the tube is 7.0 cm
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According to the continuity equation, the rate at which mass enters the system equals the rate at which mass exits in any steady state process.

An equation that explains the movement of a particular quantity is a continuity equation, also known as a transport equation. Although it can be applied generally to any significant quantity, it is extremely simple and useful when used with preserved quantities.

The radius is seven centimeters, and the mass flow rate is 0 to 5 kg/s. Find the mass flow rate at a point with a 3.5 cm radius. We can consequently deduce that based on the equation. As we all know, the mass flow rate is constant.

If the rate of mass entering and leaving the system is equal, the rate of mass leaving the system should be processed.

The mass flow rate air section A and the mass flow rated section B are equivalent, according to the continuity equation. Mass flow rate in section B is therefore 0.02, or five kilograms per second.

To know more about continuity equation, click on the link below:

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