Answer:
Magnitude of the induced emf is 11.62 V
Explanation:
Given:
No. of turns of the circular coil, N=185
Radius, R=4.50 cm=0.045 m
No. of turns of solenoid per meter(m), n=350
a=12.5 A
b=2.10
Now,
To determine the emf induced in the coil at t = 1.50 s:
The given equation is:
Now,
Now, substituting the respective values:
Now,
where,
A=Area=
Thus,
They are both sites of new cell formation.
Answer:
19.9 N/m
Explanation:
From the question,
Applying Hook's law
F = Ke.................. Equation 1
Where F = Force on the spring, k = spring constant, e = extension
But the force on the spring is the weight of the mass
Therefore,
mg = ke.................. Equation 2
Where m = mass. g = acceleration due to gravity
make e the subject of the equation
e = mg/e................ Equation 3
Given: m = 455 g = 0.455 kg, e = 22.4 cm = 0.224 m,
Constant: g = 9.8 m/s²
Substitute these values into equation 3
e = (0.455×9.8)/0.224
e = 19.9 N/m
Answer:
Tension on each chain: 30.28N
Explanation:
We start by drawing a free-body diagram of all the forces acting on the flower pot. These are:
1) the weight of the flower pot which is the product of the pot's mass time the acceleration of gravity "g" (pictured in green and represented by in the diagram), and
2) the two tensions in the chains, which since they are symmetric, are of the same size, pictured in red color and represented by the letter "T" in the diagram.
We also decompose the tensions T in two components each (a vertical component V and a horizontal component h) which are pictured in blue.
All vertical forces must cancel out since the object is in static equilibrium, so:
The horizontal components h are equal, and since they act in opposite directions, they indeed cancel out.
Now to calculate the tension, we use the fact that we know the angle between T and the component V. They in fact are related via the cosine of the angle because they are the hypotenuse and the adjacent side in a right angle triangle:
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