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wolverine [178]
4 years ago
5

The most common source of radiation is Radon True or false

Chemistry
1 answer:
CaHeK987 [17]4 years ago
8 0
Radon is a naturally occurring radioactive gas. It comes from radioactive decay of uranium.

It is usually found in igneous rock and soil, but in some cases, well water can also be a source of radon.
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4. After reaching the final titration endpoint the solution will be cloudy white. As time goes on the solution will turn back to
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Answer: hello some part of your question is missing below is the missing part

In an experiment to determine the % of ascorbic acid in Vitamin C Tablets by Titration with Potassium Bromate,

answer:

Oxidation half reaction of Vitamin C

Explanation:

The solution will turn cloudy dark purple even after reaching endpoint when allowed to settle with time. because of the Oxidation half reaction of Vitamin C. also during the Titration process few drops of starch solution will be added to help determine the endpoint of the experiment .

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Nitrogen can exist as a solid, a liquid, or a gas. Which of the following lists the
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I would say it’s 4

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Charlie the Chemist heats a 62.51 g piece of copper from 22.9°C to 345.0°C. Calculate the amount
Ivanshal [37]
  • Mass=m=62.51g
  • Initial temperature=T_i=22.9°C
  • Final temperature=T_f=345.0°C
  • Specific heat of copper=0.0920cal/g°C
  • ∆T=T_f-T_i=345-22.9=322.1°C

\\ \tt\hookrightarrow Q=mc\Delta T

\\ \tt\hookrightarrow Q=62.1(0.0920)(322.1)

\\ \tt\hookrightarrow Q=1840.22172cal

\\ \tt\hookrightarrow Q=1840.222cal

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Read 2 more answers
Calculate the Kelvin temperature to which 10.0 L of a gas at 27 °C would have to be heated to change the volume to 12.0 L. Units
KatRina [158]

Hello!

For this problem, we will be applying <em>Charles' Law</em>:

V1/T1 = V2/T2

Now that we have the formula, let's convert the temperature to Kelvin.

27 + 273 = 300K

Let's plug everything in now!

10/300 = 12.0/x

Simplified:

1/30 = 12.0/x

Cross-multiply:

1x = 30*12.0

<u>x = 360</u>

<em>Check!</em>

10/300 = 12/360

300*12 = 360*10

3600 = 3600

Therefore, you would have to heat the gas at a temperature of 360K in order to raise the volume to 12.0L.

 

4 0
3 years ago
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