What type of elements form metallic bonds?

A pendulum starts out at its highest point with 10 Joules of Potential Energy. When it reaches the lowest point of its swing, ho

vagabundo [1.1K]

Idk 0? I thought when an object is at potential energy it at its lowest point. Sorry guess this doesn't help If I just had the lesson I may be able 2 help.

7 0

3 years ago

A bicycle tire is filled with air to a pressure of 100. psi at a temperature of 19C. Riding the bike on asphalt on a hot day inc

Zigmanuir [339]

Considering the direct relationship between pressure and temperature, the new pressure in the bicycle tire would be 63.01 psi

The general gas laws is given by:

P1V1/T1 = P2V2/T2

Where P1 = initial pressure V1 = initial volume T1 = initial temperature, P2 = final pressure, V2 = final volume, and T2 = final temperature.

In this case, P1 = 100 psi, V1 = 1, T1 = 19+273 = 292, P2 = ?, V2 = 1.4, T2 = 58+273 = 331

P2 = P1V1T2/T1V2

= 100x1x292/331x1.4

= 63.01 psi

More on gas laws can be found here: brainly.com/question/1190311

5 0

2 years ago

Un tecnico di laboratorio deve preparare una soluzione di carbonato di sodio decaidrato, Na2CO3⋅ 10 H2O per eseguire alcune anal

fiasKO [112]

Answer:

1. 3.70 g Na₂CO₃·10H₂O

2. 50.0 mL of the first solution

Explanation:

1. Prepare the solution

(a) Calculate the molar mass of Na₂CO₃·10H₂O

$\begin{array}{rrr}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 2\times22.99 & 45.98\\\text{1C} & 1\times 12.01 & 12.01\\\text{13O}&13 \times16.00 & 208.00\\\text{20H}&20 \times 1.008 & 20.16\\&\text{TOTAL =} & \mathbf{286.15}\\\end{array}$

The molar mass of Na₂CO₃·10H₂O is 286.15 g/mol.

(b) Calculate the moles of Na₂CO₃·10H₂O

$\text{Moles of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}\\= \text{0.250 L solution} \times \dfrac{\text{0.0500 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}{\text{1 L solution}}\\\\= \text{0.0125 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}$

(c) Calculate the mass of Na₂CO₃·10H₂O

$\text{Mass of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O }\\= \text{0.012 50 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O } \times \dfrac{\text{296.15 g Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}{\text{1 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}\\\\= \text{3.70 g Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}\\\text{You need $\large \boxed{\textbf{3.70 g}}$ of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}$

2. Dilute the solution

We can use the dilution formula to calculate the volume needed.

V₁c₁ = V₂c₂

Data:

V₁ = ?; c₁ = 0.0500 mol·L⁻¹

V₂ = 100 mL; c₂ = 0.0250 mol·L⁻¹

Calculation:

$\begin{array}{rcl}V_{1}c_{1} & = & V_{2}c_{2}\\V_{1}\times \text{0.0500 mol/L} & = & \text{100 mL} \times\text{0.0250 mol/L}\\0.0500V_{1}& = & \text{2.500 mL}\\V_{1}&=& \dfrac{\text{2.500 mL}}{0.0500}\\\\& = & \text{50.0 mL}\\\end{array}\\\text{You need $\large \boxed{\textbf{50.0 mL}}$ of the concentrated solution.}$

7 0

3 years ago

Which temperature most likely corresponds to the asthenosphere?

iren2701 [21]

Answer:

A. 1613 °C

Explanation:

The asthenosphere is located just below the Earth’s crust.

It must be molten or semi-molten, so that convection currents can move the tectonic plates above it.

Rocks start to melt at about 1300 °C, so a temperature of 1613 °C sounds about right.

4 0

3 years ago

Read 2 more answers

What is the freezing point of an aqueous suger (C12H22O11) solution that boils at 110C°?

AURORKA [14]

Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.

<h3>What is the freezing point?</h3>

The temperature at which a liquid solidifies.

Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.

Learn more about the freezing point here:

brainly.com/question/3543605

#SPJ1

7 0

2 years ago

What type of elements form metallic bonds?​

What type of elements form metallic bonds?