Compounds are not possible to be separated by physical means
Answer:
34 g of NH₃ were produced in the reaction
Explanation:
N₂ (g) + 3H₂ (g) → 2NH₃ (g)
Moles of N₂ → 28 g / 28 g/m = 1 mol
Moles of H₂ → 25g / 2 g/m = 12.5 moles
Clearly, the limiting is the nitrogen.
1 mol of N₂ produced 2 moles of ammonia
So, If I have 1 mol, I'll produce the same amount
2 moles of NH₃ = Mol . Molar mass
2 m . 17 g/m = 34 g
reactivity! when something reacts to another substance, its a chemical change. When something melts, boils, or changes color, it is still the same substance, therefore is physical
Given data:
Sublimation of K
K(s) ↔ K(g) ΔH(sub) = 89.0 kj/mol
Ionization energy for K
K(s) → K⁺ + e⁻ IE(K) = 419 Kj/mol
Electron affinity for Cl
Cl(g) + e⁻ → Cl⁻ EA(Cl) = -349 kj/mol
Bond energy for Cl₂
1/2Cl₂ (g) → Cl Bond energy = 243/2 = 121.5 kj/mol
Formation of KCl
K(s) + 1/2Cl₂(g) → KCl(s) ΔHf = -436.5 kJ/mol
<u>To determine:</u>
Lattice energy of KCl
K⁺(g) + Cl⁻(g) → KCl (s) U(KCl) = ?
<u>Explanation:</u>
The enthalpy of formation of KCl can be expressed in terms of the sum of all the above processes, i.e.
ΔHf(KCl) = U(KCl) + ΔH(sub) + IE(K) + 1/2 BE(Cl₂) + EA(Cl)
therefore:
U(KCl) = ΔHf(KCl) - [ΔH(sub) + IE(K) + 1/2 BE(Cl₂) + EA(Cl)]
= -436.5 - [89 + 419 + 243/2 -349] = -717 kJ/mol
Ans: the lattice energy of KCl = -717 kj/mol
