For this case what we must do is find the speed of Esmeralda.
For this, we look for the rate of change of the function
We have then:
Substituting values:
Rewriting:
Answer:
Esmeralda's average rate during her trip is 5 miles per hour.
A car leaving a stop sign accelerates constantly from a speed of 0 feet per second to reach a speed of 44 feet per second. The d
1 answer:
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Answer: y = - x - 6
Step-by-step explanation:
The line crosses the y intercept at y = -6
The slope of the graph looks negative, as it extends from the top left quadrant to the bottom right quadrant.
A key trick is to use rise/run to figure out the slope:
Between each dot on the line, it rises 2 and runs -3 (negative because the direction is left).
So your equation would be: y = - x - 6
<h3>Answer: C) 142 degrees</h3>
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Explanation:
Extend segment MN such that it intersects side ST. Mark the intersection as point A. See the diagram below.
We're given that angle MNT is 72 degrees. The angle TNA is equal to 180-(angle MNT) = 180 - 72 = 108 degrees, since angles MNT and TNA add to 180.
For now, focus entirely on triangle TNA. We see from the diagram that T = 34 and we just found that N = 108. Let's find angle A
A+N+T = 180
A+108+34 = 180
A+142 = 180
A = 180-142
A = 38
So angle NAT is 38 degrees.
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Since segment MA is an extension of MN, and because MN || SQ, this means MA is also parallel to SQ.
We found at the conclusion of the last section that angle NAT was 38 degrees. Angles QST and NAT are corresponding angles. They are congruent since MA || SQ. This makes angle QST to also be 38 degrees
----------------------------
The angles QSR and QST are a linear pair, so they are supplementary
(angle QSR) + (angle QST) = 180
angle QSR = 180 - (angle QST)
angle QSR = 180 - 38
angle QSR = 142 degrees
Answer:
The perimeter is 14 units
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Step-by-step explanation:
Given
Required
Determine the perimeter
To do this, we simply calculate the distance between the sides of the rectangle i.e. AB, BC, CD and DA.
Distance (d) is calculated using:
For AB
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For BC
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For CD
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For DA
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So, the perimeter (P) is:
<em>The perimeter is 14 units</em>