Answer: 350 newton
Explanation:
Force needed = ?
mass = 10kg
Acceleration = 35m/s2 (The SI unit of acceleration is metre per second square)
Recall that Force is the product of mass of an object and the acceleration by which it moves.
Force = mass x acceleration
Force = 10kg x 35m/s2
Force = 350N
Thus, the force needed is 350 newton
That thing is used as a lever.
Complete Question
A small block is released from rest at the top of a frictionless incline. The distance from the top of the incline to the bottom, measured along the incline, is 3.40 m. The vertical distance from the top of the incline to the bottom is 1.09 m. If , what is the acceleration of the block as it slides down the incline plane
Answer:
The acceleration is
Explanation:
From the question we are told that
The distance from top to bottom of the inclined plane measured along the incline is
The distance from top to bottom of the inclined plane measured along the vertical axis is
According to the SOHCAHTOA rule
=>
substituting values
=>
T
The acceleration of a block on a frictionless inclined plane is mathematically represented as
substituting values
Answer:
How to find the maximum height of a projectile?
if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest. ...
if α = 45°, then the equation may be written as: ...
if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.
Answer: At 34°c
Explanation:
Using The Arrhenius Equation:
k = Ae − Ea/RT
k represents rate constant
A represents frequency factor and is constant
R represents gas constant which is = 8.31J/K/mol
Ea represents the activation energy
T represents the absolute temperature.
By taking the natural log of both sides,
ln k = ln A- Ea/RT
Reactions at temperatures T1 and T2 can be written as;
ln k1= ln A− Ea/RT1
ln k2= ln A− Ea/RT2
Therefore,
ln(k1/k2) = −Ea/RT1 + Ea/RT2
Since k2=2k1 this becomes:
ln(1/2) = Ea/R*[1/T2 − 1/T1]
Theefore,
-0.693 = 37.2 x 10^3/8.31 * [ 1/T2 - 1/293]
1/T2 - 1/293 = -1.55 x 10^-4
1/T2 = -1.55 x 10^-4 + 34.13x 10^-4
1/T2 = 32.58 x 10^-4
Therefore T2 = 307K
T2 = 307 - 273 = 34 °c