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expeople1 [14]
2 years ago
6

What is the Gravitational strength of the planet Eris

Physics
1 answer:
BabaBlast [244]2 years ago
3 0
<h3>Answer:</h3>

0.82 m/s²

<h3>How?</h3>

Though its gravity is weak compared to earth, Eris has the strongest gravity out of all the dwarf planets: 0.82 m/s².

<h3>How Is Eris Important?</h3>

Eris is the <u>largest</u> dwarf planet in the Solar System, and the <u>ninth largest body orbiting our Sun.</u> The discovery of Eris was so important because it was a celestial body larger than Pluto, which forced astronomers to consider, for the first time in history, what the definition of a planet truly is!

Hope this helps you!! :D

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Suppose a log’s mass is 5 kg. After burning, the mass of the ash is 1 kg. What can you predict has happened to the other 4 kg?
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It transformed into ash particles and a slight gaseous state

Explanation:

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What is 1 abiotic factors shown in this diagram?
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B. The water

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What is the mass of a 200 kg object on Venus?
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8 0
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What is the momentum of a 50-kilogram ice skater gliding across the ice at a speed of 5 m/s? (1 point)
serious [3.7K]
Momentum is a term used to quantify the motion of an object has. It is calculated as the the product of the object's mass and the velocity. It is expressed as:

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Therefore, the correct answer is the last option.
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3 years ago
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The vapor pressure of benzene, C6H6, is 40.1 mmHg at 7.6°C. What is its vapor pressure at 60.6°C? The molar heat of vaporization
ANEK [815]

Answer:

The vapor pressure at 60.6°C is 330.89 mmHg

Explanation:

Applying Clausius Clapeyron Equation

ln(\frac{P_2}{P_1}) = \frac{\delta H}{R}[\frac{1}{T_1}- \frac{1}{T_2}]

Where;

P₂ is the final vapor pressure of benzene = ?

P₁ is the initial vapor pressure of benzene = 40.1 mmHg

T₂ is the final temperature of benzene = 60.6°C = 333.6 K

T₁ is the initial temperature of benzene = 7.6°C = 280.6 K

ΔH is the molar heat of vaporization of benzene = 31.0 kJ/mol

R is gas rate = 8.314 J/mol.k

ln(\frac{P_2}{40.1}) = \frac{31,000}{8.314}[\frac{1}{280.6}- \frac{1}{333.6}]\\\\ln(\frac{P_2}{40.1}) = 3728.65 (0.003564 - 0.002998)\\\\ln(\frac{P_2}{40.1}) = 3728.65  (0.000566)\\\\ln(\frac{P_2}{40.1}) = 2.1104\\\\\frac{P_2}{40.1} = e^{2.1104}\\\\\frac{P_2}{40.1} = 8.2515\\\\P_2 = (40.1*8.2515)mmHg = 330.89 mmHg

Therefore, the vapor pressure at 60.6°C is 330.89 mmHg

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3 years ago
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